如果用户选中四个复选框之一,则尝试启用提交按钮。
这是我的Javascript:
<script>
$(function() {
$('input.required').click(function() {
var unchecked = $('input.required:not(:checked)').length;
if (unchecked == 0) {
$('#submitBtn').removeAttr('disabled');
}
else {
$('#submitBtn').attr('disabled', 'disabled');
}
});
});
</script>
这是我的表单元素:
<input class="required" name="equipment_dropped_off" type="checkbox" id="check1" value="equipment_dropped_off"/>
<label for="check1"><span class="style1">Equipment Dropped Off </span></label>
<span class="style1">
<input class="required" name="work" type="checkbox" id="check2" value="work"/>
<label for="check2">Work performed </label>
<input class="required" name="payment" id="check3" type="checkbox" value="payment" />
<label for="check3">Payment Recieved </label>
<input class="required" name="equipment_picked_up" id="check4" type="checkbox" value="equipment_picked_up" />
<label for="check4">Equipment Picked Up</label>
<input class='btn-style' data-rol="none" id="submitBtn" type="submit" name="submitBtn" value="STEP 4 - SAVE SIGNATURE" disabled="disabled">
一旦我选中一个框,浏览器控制台就会显示:无法将属性“ disabled”设置为null
我究竟做错了什么?
您在第一个输入中使用了错误的ID
<input class="required" name="equipment_dropped_off" type="checkbox" id="check1" value="equipment_dropped_off" onclick = "document.getElementById('submitBtn').disabled=false;"/>
另外,您还应该更改JavaScript代码:
$(function() {
$('input.required').click(function() {
var checked = $('input.required:checked').length;
if (checked != 0) {
$('#submitBtn').removeAttr('disabled');
}
else {
$('#submitBtn').attr('disabled', 'disabled');
}
});
});
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