我有两个表,每个表都有许多属性。每个属性都有我想要的属性,我试图编写一个查询以获取这些属性,并将它们放入三列中。
表A
LOCATION_NUMBER (varchar2(20Byte)),
BEGIN (NUMBER (3,0)),
BEGIN_DEC (NUMBER (4,3)),
END (NUMBER (3,0)),
END_DEC (NUMBER (4,3))
表B
LOCNUM (NUMBER (15,0)),
START (VARCHAR2(6 BYTE)),
START_POS (NUMBER (5,3)),
FINISH (VARCHAR2 (6 BYTE)),
FINISH_POS (NUMBER (5,3)).
我从查询中想要的是一个具有三个属性的表,然后按位置先对这些表进行排序,然后再开始。
表C,
LOCATION,
START,
END
这是一个例子:
A:
LOCATION_NUMBER BEGIN BEGIN_DEC END END_DEC
I 26 8 0.63 13 0.99
I 32 144 0 151 0.82
I 35 22 0.29 55 0.09
I 35 128 0.1 67 0.9
I 35 0 0 22 0.28
B:
LOC_NUM START START_POS FINISH FINSIH_POS
227 98 0.56 100 0
35 149 0.25 151 0.55
96 156 0.23 156 1.26
11 263 2.56 263 4.52
结果集:
LOCATION START END
26 8.63 13.99
32 144 151.82
35 22.29 55.09
35 128.1 67.9
35 0 22.28
227 98.56 100
35 149.25 151.55
96 156.23 157.26
11 265.56 267.52
我尝试了一些查询,可以从每个表中获得所需的结果,我只需要知道如何将它们组合为一个,以使事情变得更容易,因为我想要该表,因此,每个表都有10个-我不想担心的20多个属性。
Select to_number(trim(regexp_substr(A.LOCATION_NUMBER ,'[^ ]+', 1, 2))) AS LOCATION,
(to_number(trim(A.BEGIN)) + to_number(trim(A.BEGIN_DEC))) AS START,
(to_number(trim(A.END)) + to_number(trim(A.END_DEC))) AS END
FROM A
ORDER BY to_number(trim(regexp_substr(A.LOCATION_NUMBER,'[^ ]+', 1, 2)));
SELECT B.LOC_NUM AS LOCATION,
(to_number(trim(B.START)) + to_number(trim(B.START_POS))) AS START,
(to_number(trim(B.FINISH)) + to_number(trim(B.FINISH_POS))) AS END
FROM B
ORDER BY B.LOCATION, START;
假设查询工作正常,您只需要union all
:
Select to_number(trim(regexp_substr(A.LOCATION_NUMBER ,'[^ ]+', 1, 2))) AS LOCATION,
to_number(trim(A.BEGIN)) + to_number(trim(A.BEGIN_DEC)) AS START,
to_number(trim(A.END)) + to_number(trim(A.END_DEC)) AS END
FROM A
UNION ALL
SELECT B.LOC_NUM AS LOCATION,
to_number(trim(B.START)) + to_number(trim(B.START_POS)) AS START,
to_number(trim(B.FINISH)) + to_number(trim(B.FINISH_POS)) AS END
FROM B
ORDER BY B.LOCATION, START;
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我来说两句