如何制作Android Guessing Game将猜测次数限制为3次尝试，之后将显示一条消息

Beda 发表于 Dev

不同的

我需要制作到目前为止有3次尝试限制的android猜测游戏，之后将显示诸如游戏结束之类的消息，但是我不知道如何进行操作，因为我还是编程新手，所以我会感谢你的帮助

到目前为止的Android代码：

import java.util.Random;
import android.app.Activity;
import android.graphics.Color;
import android.os.Bundle;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
public class Task1Activity extends Activity {

private TextView tvPlayer;
private EditText eName;
private Button butSubmit;
private TextView nameOutput;
private TextView tvNumber;
private EditText eNumber;
private TextView numOutput;
private Button butGuess;
private Button butStart;
private String name_output;
private String number_output;
private TextView tvTries;
private TextView tvTries2;
public static int N;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.task1_layout);
    //Reference the input and output views on the interface
    tvPlayer = (TextView) findViewById(R.id.tvPlayer);
    eName = (EditText) findViewById(R.id.eName);
    butSubmit = (Button) findViewById(R.id.butSubmit);
    tvNumber = (TextView) findViewById(R.id.tvNumber);
    eNumber = (EditText) findViewById(R.id.eNumber);
    butGuess = (Button) findViewById(R.id.butGuess);
    butStart = (Button) findViewById(R.id.butStart);
    nameOutput = (TextView) findViewById(R.id.nameOutput);
    numOutput = (TextView) findViewById(R.id.numOutput);
    tvTries = (TextView) findViewById(R.id.tvTries);
    tvTries2 = (TextView) findViewById(R.id.tvTries2);
}


public void addClick1(View Button){
      name_output = eName.getText().toString(); //get the existing comments
      nameOutput.setText(name_output);//Display the new comments
    } public void addClick2(View Button){
Random r = new Random();
int Low = 0;
int High = 20;
N = r.nextInt(High-Low) + Low;
}

public void addClick3(View Button){



      number_output = eNumber.getText().toString(); //get the existing comments

      try {
            int compareNum = Integer.parseInt(number_output);
             if(compareNum == N){
                  numOutput.setText(number_output + " Good Guess!");//Display the new comments
                  numOutput.setBackgroundColor(Color.GREEN);
              }else if(compareNum > N){
                  numOutput.setText(number_output + " is too HIGH!");//Display the new comments
                  numOutput.setBackgroundColor(Color.RED);
              }else if(compareNum < N){
                  numOutput.setText(number_output + " is too LOW!");//Display the new comments
                  numOutput.setBackgroundColor(Color.RED);
              }
        }
        catch (NumberFormatException e) {
        }
    }
}

乔治·安东尼奥利

您必须计算点击次数，例如：

public void addClick2(View Button){
Random r = new Random();
int Low = 0;
int High = 20;
int count = 0;
N = r.nextInt(High-Low) + Low;
}

public void addClick3(View Button){
      count++;
      number_output = eNumber.getText().toString(); //get the existing comments

      try {
            int compareNum = Integer.parseInt(number_output);
             if(compareNum == N){
                  numOutput.setText(number_output + " Good Guess!");//Display the new comments
                  numOutput.setBackgroundColor(Color.GREEN);
              }else if(compareNum > N){
                  numOutput.setText(number_output + " is too HIGH!");//Display the new comments
                  numOutput.setBackgroundColor(Color.RED);
              }else if(compareNum < N){
                  numOutput.setText(number_output + " is too LOW!");//Display the new comments
                  numOutput.setBackgroundColor(Color.RED);
              }
        }
        catch (NumberFormatException e) {
        }
        if(count == 3){
            //set your game over message
        }
    }
}