我正在尝试创建一个过滤器,以使用grep和子集一起从数据集中删除行。
样本数据集:
id <- 1:10
problem <- c("a" , "b", "c", "d", "a","b","c","a", "b", "a")
solution1 <- c("eat", "sleep", "drink", "play", "sleep", "play", "play", "drink", "play", "eat")
solution2 <- c("read", "read", "eat", "drink", "eat", "sleep", "eat", "read", "eat", "play")
df <- c(id, problem, solution1, solution2)
我正在尝试删除问题为“ a”的行,并在solution1或solution2中都包含“ eat”。
结果是应删除ID 1、5和10。
我试过使用:
df <- subset(df, problem=="a" & !(grepl("eat", df)))
和
df <- df[!grepl("eat", df) & grepl("a", df$problem)]
在StackOverflow或我用Google搜索的其他网站上似乎找不到类似的解决方案。
如果有人可以帮助,将不胜感激。谢谢!
首先,如果要使用数据框,则应使用data.frame而不是c:
df <- data.frame(id, problem, solution1, solution2)
然后,您可以例如这样子集(本身无需使用子集)
df2 <- df[!(grepl("a", df$problem) &
(grepl("eat", df$solution1) |
grepl("eat", solution2))),]
# id problem solution1 solution2
# 2 2 b sleep read
# 3 3 c drink eat
# 4 4 d play drink
# 6 6 b play sleep
# 7 7 c play eat
# 8 8 a drink read
# 9 9 b play eat
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