我以以下方式获取字符串，日期以随机模式结尾。但是它将仅包含下划线，斜杠，数字或连字符。
TRAVEL_DELAY_01072015
TRAVEL_DELAY_01_07_2015
TRAVEL_DELAY_2015/01/04
TRAVEL_DELAY_2015-01-04
我只需要从上述字符串中取出TRAVEL_DELAY。我为此使用正则表达式，但无法正常工作：
m = re.match("^(.*)[_0-9\/.]+", abovestring)
如果您只想分割日期：
s="""TRAVEL_DELAY_01072015
TRAVEL_DELAY_01_07_2015
TRAVEL_DELAY_2015/01/04
TRAVEL_DELAY_2015-01-04"""
for line in s.splitlines():
date = line.split("_",2)[-1]
01072015
01_07_2015
2015/01/04
2015-01-04
或者str.replace，不需要正则表达式：
for line in s.splitlines():
date = line.replace("TRAVEL_DELAY_","")
print(date)
01072015
01_07_2015
2015/01/04
2015-01-04
如果您实际上是想解析日期，则可以使用dateutil并修复字符串：
from dateutil import parser
for line in s.splitlines():
date = line.replace("TRAVEL_DELAY_","")
if any(ch in date for ch in ("/","-","_")):
print(parser.parse(date.replace("_","-")))
else:
date = "{}-{}-{}".format(date[:2],date[2:4],date[4:])
print(parser.parse(date))
2015-01-07 00:00:00
2015-01-07 00:00:00
2015-01-04 00:00:00
2015-01-04 00:00:00
如果数字仅在日期中，并且您实际上想要的是字符串而不是日期：
s="""TRAVEL_DELAY_01072015
TRAVEL_DELAY_01_07_2015
TRAVEL_DELAY_2015/01/04
Travel_Delay_Data_2015/01/04
TRAVEL_DELAY_2015-01-04"""
for line in s.splitlines():
ind = next(ind for ind, ele in enumerate(line) if ele.isdigit())
s = line[:ind-1]
print(s)
TRAVEL_DELAY
TRAVEL_DELAY
TRAVEL_DELAY
Travel_Delay_Data
TRAVEL_DELAY
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