如何设置ListView的ItemsSource？

在这里，我定义了数据myListOfEmployeeObjects：

public class App : Application
{
    public List<Employee> myListOfEmployeeObjects;

    public App ()
    {
        Employee emp1 = new Employee () {
            FirstName = "Max",
            LastName = "Mustermann",
            Twitter = "@fake1"
        };
        Employee emp2 = new Employee () {
            FirstName = "Evy",
            LastName = "Mustermann",
            Twitter = "@fake2"
        };
        myListOfEmployeeObjects = new List<Employee> {
            emp1, emp2
        };
        MainPage = new NavigationPage (new EmployeeListPage ());
    }
}

比起我的XAML，我在其中设置了ItemsSource：

<ListView x:Name="listView"
                IsVisible="false"
                ItemsSource="{x:Static local:App.myListOfEmployeeObjects}"
                ItemSelected="EmployeeListOnItemSelected">

应该行吗？因为我得到

Xamarin.Forms.Xaml.XamlParseException：在xmlns中找不到类型的应用程序

public partial class EmployeeListPage : ContentPage {

    private ListView listView;

    private void InitializeComponent() {
        this.LoadFromXaml(typeof(EmployeeListPage)); // here the exception is thrown
        listView = this.FindByName <ListView>("listView");
    }
}

如何设置ItemsSourceXAML？

编辑：

现在，我尝试了来自user2425632的建议，如果执行以下更改，它将起作用：

1. 添加xmlns:local="clr-namespace:HelloXamarinFormsWorld;assembly=HelloXamarinFormsWorld"到我的XAML文件

现在看起来像下面

<?xml version="1.0" encoding="UTF-8"?>
<ContentPage xmlns="http://xamarin.com/schemas/2014/forms"
             xmlns:x="http://schemas.microsoft.com/winfx/2009/xaml"
             xmlns:local="clr-namespace:HelloXamarinFormsWorld;assembly=HelloXamarinFormsWorld"
             x:Class="HelloXamarinFormsWorld.EmployeeListPage"
             Title="Employee List">
    <ContentPage.Content>

当然，您必须更改名称以使其适合您的项目。

2. 显示列表视图

我删除了IsVisible和ItemSelected。

<ListView ItemsSource="{x:Static local:App.myListOfEmployeeObjects}">

3. 使一切静止

它必须是静态的，否则您将得到

找不到local：App.myListOfEmployeeObjects的静态成员

public static List<Employee> myListOfEmployeeObjects { private set; get; }

public static void GetAllEmployees(){
    Employee emp1 = new Employee () {
        FirstName = "Max",
        LastName = "Mustermann",
        Twitter = "@fake1"
    };
    Employee emp2 = new Employee () {
        FirstName = "Eva",
        LastName = "Mustermann",
        Twitter = "@fake2"
    };
    myListOfEmployeeObjects = new List<Employee> {
        emp1, emp2
    };
}

public App ()
{
    GetAllEmployees ();
    MainPage = new NavigationPage (new EmployeeListPage ());
}