我有有效的XSD,但我无法制作xml,不适合它。
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<xs:schema xmlns="urn:hl7-org:v3" xmlns:xs="http://www.w3.org/2001/XMLSchema"
targetNamespace="urn:hl7-org:v3"
elementFormDefault="qualified">
<xs:element name="Main" type="Main"/>
<xs:complexType name="Child1">
<xs:sequence>
<xs:element name="f1" type="xs:string"/>
</xs:sequence>
</xs:complexType>
<xs:complexType name="Child2">
<xs:sequence>
<xs:element name="f1" type="xs:string"/>
</xs:sequence>
</xs:complexType>
<xs:complexType name="Main">
<xs:sequence>
<xs:choice>
<xs:element name="child1" type="Child1"
nillable="true"
minOccurs="1"
maxOccurs="1"/>
<xs:element name="child2" type="Child2"
nillable="true"
minOccurs="1"
maxOccurs="1"/>
</xs:choice>
</xs:sequence>
</xs:complexType>
</xs:schema>
如果这不可能,那么架构为何有效?使用JAXB为此模式生成源,创建对象,但验证未通过-[发现无效的内容以元素'child1'开始。此时,预计不会有任何子元素。]
import cz.atria.common.datagenerator.ValueProvider;
import cz.atria.common.datagenerator.ValueProviderRandom;
import org.hl7.v3.Child1;
import org.hl7.v3.Main;
import org.hl7.v3.ObjectFactory;
import org.junit.Test;
import javax.xml.XMLConstants;
import javax.xml.bind.*;
import javax.xml.validation.Schema;
import javax.xml.validation.SchemaFactory;
import java.io.File;
public void test1() throws Exception {
JAXBContext jaxbContext = JAXBContext.newInstance(Main.class.getPackage().getName());
SchemaFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
Schema schema = schemaFactory.newSchema(new File("D:\\cts2\\jaxbtest\\src\\main\\xsd\\schema1.xsd"));
Marshaller marshaller = jaxbContext.createMarshaller();
ObjectFactory of = new ObjectFactory();
marshaller.setSchema(schema);
Main main = new Main();
Child1 child1 = new Child1();
child1.setF1("test");
main.setChild1(child1);
final ValidationEventHandler validationEventHandler = marshaller.getEventHandler();
marshaller.setEventHandler(new ValidationEventHandler() {
@Override
public boolean handleEvent(ValidationEvent event) {
/*if(event.getLocator().getObject() instanceof Child1) {
return true;
} else {
return validationEventHandler.handleEvent(event);
}*/
return validationEventHandler.handleEvent(event);
}
});
System.out.println(marshaller.getEventHandler());
marshaller.marshal(main, System.out);
}
基于您问题中的相同代码,我假设您使用了如下所示的外部绑定文件来摆脱JAXBElement
属性。
<jaxb:bindings
xmlns:jaxb="http://java.sun.com/xml/ns/jaxb"
jaxb:version="2.0"
xmlns:xjc= "http://java.sun.com/xml/ns/jaxb/xjc"
jaxb:extensionBindingPrefixes="xjc">
<jaxb:globalBindings generateElementProperty="false">
<xjc:simple />
</jaxb:globalBindings>
</jaxb:bindings>
这将为您提供一个Main
类似于以下内容的类:
@XmlRootElement(name = "Main")
public class Main {
@XmlElement(nillable = true)
protected Child2 child2;
@XmlElement(nillable = true)
protected Child1 child1;
...
}
这将产生如下所示的XML,请注意child2
和child1
元素的存在:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<Main xmlns="urn:hl7-org:v3">
<child2 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:nil="true"/>
<child1>
<f1>test</f1>
</child1>
</Main>
您需要放回JAXBElement
属性(以区分xsi:nil="true"
为零而编组的值,还是作为选择的一部分缺少节点)。这意味着您需要generateElementProperty="false"
从外部绑定文件中删除。这将为您提供一个类似于以下内容的Main类:
@XmlRootElement(name = "Main")
public class Main {
@XmlElementRef(name = "child2", namespace = "urn:hl7-org:v3", type = JAXBElement.class, required = false)
protected JAXBElement<Child2> child2;
@XmlElementRef(name = "child1", namespace = "urn:hl7-org:v3", type = JAXBElement.class, required = false)
protected JAXBElement<Child1> child1;
...
}
这将产生类似于以下内容的XML,并且可以正确验证:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<Main xmlns="urn:hl7-org:v3">
<child1>
<f1>test</f1>
</child1>
</Main>
本文收集自互联网,转载请注明来源。
如有侵权,请联系[email protected] 删除。
我来说两句