假设我有两个表Task和Company。Company有列id和name。Task有两列customerId，providerId它们链接回的id列Company。
使用Querydsl如何在Company表上加入两次，以便可以获取和name指定的每个公司的？customerIdproviderId
也许可以更好地解释我正在尝试的代码：
Configuration configuration = new Configuration(templates);
JPASQLQuery query = new JPASQLQuery(this.entityManager, configuration);
QTask task = QTask.task;
QCompany customer = QCompany.company;
QCompany provider = QCompany.company;
JPASQLQuery sql = query.from(task).join(customer).on(customer.id.eq(task.customerId))
.join(provider).on(provider.id.eq(task.providerId));
return sql.list(task.id, customer.name.as("customerName"), provider.name.as("providerName"));
生成SQL：
select task.id, company.name as customerName, company.name as providerName from task join company on company.id = task.customerId
我真的很希望这样：
select task.id, customer.name as customerName, provider.name as providerName from task join company as customer on customer.id = task.customerId join company as provider on provider.id = task.providerId
我不知道如何为要加入的表加上别名，以便区分客户名和提供商名。我尝试这样做，new QCompany("company as provider")但是没有用。有人知道该怎么做吗？
如果您需要变量，请执行以下操作
QCompany customer = new QCompany("customer");
QCompany provider = new QCompany("provider");
重新分配默认变量QCompany.company无济于事
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我来说两句