如何使用TFS API 2013获取所有迭代路径

aqwert 发表于 Dev

阿克韦特

我使用TFS API库已有一段时间，并且在与TFS 2010交互以获取迭代路径时使用以下代码（此页中的代码）...

public IList<string> GetIterationPaths(Project project)
{
   List<string> iterations = new List<string>();
   foreach (Node node in project.IterationRootNodes)
      AddChildren(string.Empty, node, iterations);
   return iterations;
}

private void AddChildren(string prefix, Node node, List<string> items)
{
   items.Add(node.Path);
   foreach (Node item in node.ChildNodes)
      AddChildren(prefix + node.Name + "/", item, items);
}

当我希望在TFS 2013中获得所有迭代时，事情发生了变化。在TFS 2013中，迭代的概念略有更改，并且TFS 2013的API程序集没有IterationRootNodes

我已经使用以下代码获取团队迭代，但这是基于团队的，而不是针对项目的完整迭代...（目前正在获得第一团队，但可以进行编码以获取其他团队）

 var cred = new TfsClientCredentials(new WindowsCredential(), true);
 TfsTeamProjectCollection coll = new TfsTeamProjectCollection("{URI to SERVER}", cred);
 coll.EnsureAuthenticated();

 var teamConfig = coll.GetService<TeamSettingsConfigurationService>();
 var css = coll.GetService<ICommonStructureService4>();
 var project = css.GetProjectFromName(projectInfo.ProjectName);

 IEnumerable<TeamConfiguration> configs = teamConfig.GetTeamConfigurationsForUser(new[] { project.Uri.ToString() });
 TeamConfiguration team = configs.FirstOrDefault(x => x.ProjectUri == project.Uri.ToString());

 var iterations = BuildIterationTree(team, css);

这里BuildIterationTree看起来像...

 private IList<IterationInfo> BuildIterationTree(TeamConfiguration team, ICommonStructureService4 css)
    {
        string[] paths = team.TeamSettings.IterationPaths;

        var result = new List<IterationInfo>();

        foreach (string nodePath in paths.OrderBy(x => x))
        {
            var projectNameIndex = nodePath.IndexOf("\\", 2);
            var fullPath = nodePath.Insert(projectNameIndex, "\\Iteration");
            var nodeInfo = css.GetNodeFromPath(fullPath);
            var name = nodeInfo.Name;
            var startDate = nodeInfo.StartDate;
            var endDate = nodeInfo.FinishDate;

            result.Add(new IterationInfo
            {
                IterationPath = fullPath.Replace("\\Iteration", ""),
                StartDate = startDate,
                FinishDate = endDate,
            });
        }
        return result;
    }

我的问题是...我如何获得完整的迭代树，而不是针对TFS 2013的特定于团队的迭代？

可以将特定于团队的迭代配置为通过Web门户显示或不显示该迭代复选框。

埃里克

您的问题回答了我有关如何获取特定于团队的迭代的问题，因此，我能做的至少是提供可获取完整迭代层次结构的代码段。我想我最初是在此博客上找到此代码的：

    public static void GetIterations(TfsTeamProjectCollection collection,
        ICommonStructureService4 css, ProjectInfo project)
    {
        TeamSettingsConfigurationService teamConfigService = collection.GetService<TeamSettingsConfigurationService>();
        NodeInfo[] structures = css.ListStructures(project.Uri);
        NodeInfo iterations = structures.FirstOrDefault(n => n.StructureType.Equals("ProjectLifecycle"));
        XmlElement iterationsTree = css.GetNodesXml(new[] { iterations.Uri }, true);

        string baseName = project.Name + @"\";
        BuildIterationTree(iterationsTree.ChildNodes[0].ChildNodes, baseName);
    }

    private static void BuildIterationTree(XmlNodeList items, string baseName)
    {
        foreach (XmlNode node in items)
        {
            if (node.Attributes["NodeID"] != null &&
                node.Attributes["Name"] != null &&
                node.Attributes["StartDate"] != null &&
                node.Attributes["FinishDate"] != null)
            {
                string name = node.Attributes["Name"].Value;
                DateTime startDate = DateTime.Parse(node.Attributes["StartDate"].Value, CultureInfo.InvariantCulture);
                DateTime finishDate = DateTime.Parse(node.Attributes["FinishDate"].Value, CultureInfo.InvariantCulture);

                // Found Iteration with start / end dates
            }
            else if (node.Attributes["Name"] != null)
            {
                string name = node.Attributes["Name"].Value;

                // Found Iteration without start / end dates
            }

            if (node.ChildNodes.Count > 0)
            {
                string name = baseName;
                if (node.Attributes["Name"] != null)
                    name += node.Attributes["Name"].Value + @"\";

                BuildIterationTree(node.ChildNodes, name);
            }
        }
    }