下面的脚本执行应做的工作,即,它对键“向左箭头”和“向右箭头”做出反应。但是,由于键码冲突,它也会对单引号做出反应。这样就不可能在输入字段中输入该字符。可以采取任何措施吗?
<script type="text/javascript">
onload = function(){
document.onkeypress=function(e){
if(window.event) e=window.event;
var keycode=(e.keyCode)?e.keyCode:e.which;
switch(keycode){
case 37: window.location.href='set.jsp?index=5';
break;
case 39: window.location.href='set.jsp?index=7';
break;
}
}
}
</script>
当用户按下单引号键时,该e.keyCode
属性为零,该e.which
属性为39。执行String.fromCharCode(39)
将返回单引号。
您需要keyCode
if属性是否在事件对象中:
var keycode = "keyCode" in e ? e.keyCode : e.which;
这样,当该属性存在于事件对象中并且该which
属性也存在时,您将获得keyCode零。
document.onkeydown = function(event) {
event = event || window.event;
var keyCode = "keyCode" in event ? event.keyCode : event.which;
switch (keyCode) {
case 37: console.log("37 was pressed", event); break;
case 39: console.log("39 was pressed", event); break;
}
};
编辑1:其他评论者和答案正确。我忘记了您不应该通过keypress
事件检测控制键。更改为onkeydown
。
跨浏览器工作的完整HTML示例:
<!DOCTYPE HTML>
<html>
<head>
<meta charset="utf-8">
<title>Key Codes Test</title>
</head>
<body>
<script type="text/javascript">
document.onkeydown = function(event) {
event = event || window.event;
var keyCode = "keyCode" in event ? event.keyCode : event.which;
switch (keyCode) {
case 37: console.log("37 was pressed", event); break;
case 39: console.log("39 was pressed", event); break;
}
};
</script>
<input type="text" size="30">
</body>
</html>
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