我有一张像这样的桌子:
empId empSalary empDept
1 45000 IT
2 40000 IT
3 50000 SALES
4 60000 SALES
5 75000 IT
6 80000 IT
7 25000 OPS
8 30000 OPS
9 55000 MARKETING
10 60000 MARKETING
我必须将查询写为:
select empId where empSalary > avg(empSalary) for each empDept
请帮助。
试试这个:
SELECT e.empId, e.empSalary, e.empDept
FROM employee e
INNER JOIN (SELECT e1.empDept, AVG(e1.empSalary) empSalary
FROM employee e1
GROUP BY e1.empDept
) a ON e.empDept = a.empDept AND e.empSalary > a.empSalary;
编辑
SELECT e.empDept, COUNT(DISTINCT e.empid) noOfEmployees
FROM employee e
INNER JOIN (SELECT AVG(e1.empSalary) empSalary FROM employee e1) a ON e.empSalary > a.empSalary
GROUP BY e.empDept;
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我来说两句