参数化的D3js强制有向图节点定位

Roman 发表于 Dev

罗曼

我计划为动态创建的数据集的节点创建树状结构，并希望为力导向图设置所有节点的y轴坐标。换句话说，我希望节点位于层次结构（如树结构）中，而节点则可以在x轴上自由移动和优化自身。

最终结果应该是一棵树，其中的节点位于分配的级别，而不是像默认情况下那样呈放射状。同级链接不应重叠，并且应尽可能短（逻辑分组，因此希望通过力图进行此操作）。
如果有人有比这更简单的解决方案，那么我无所不能。

代码提取：

ldLinks = [
{source: "root", target: "1", source_level: 0, target_level: 1},
{source: "root", target: "2", source_level: 0, target_level: 1},
{source: "root", target: "3", source_level: 0, target_level: 1},
{source: "root", target: "4", source_level: 0, target_level: 1},
{source: "1", target: "1.1", source_level: 1, target_level: 2},
{source: "1", target: "1.2", source_level: 1, target_level: 2},
{source: "2", target: "2.1", source_level: 1, target_level: 3},
{source: "2", target: "2.2", source_level: 1, target_level: 3},
{source: "3", target: "3.1", source_level: 1, target_level: 3},
{source: "4", target: "3.2", source_level: 1, target_level: 3},
{source: "4", target: "3.3", source_level: 1, target_level: 3},
{source: "3", target: "3.2", source_level: 2, target_level: 3},
{source: "3", target: "4.1", source_level: 2, target_level: 3},
{source: "2.1", target: "5.1", source_level: 3, target_level: 4},
{source: "3.1", target: "5.1", source_level: 3, target_level: 4},
{source: "1", target: "5", source_level: 1, target_level: 4},
];

var dNodes = {};

// Compute the distinct dNodes from the ldLinks.
ldLinks.forEach(function(link) {
    link.source = dNodes[link.source] || (dNodes[link.source] = {name: link.source, level: link.source_level});
    link.target = dNodes[link.target] || (dNodes[link.target] = {name: link.target,  level: link.target_level});
});

//parameterize nodes
for (var sNodeName in dNodes) {
    //dNodes[sNodeName].fixed = (only fixed along y-axis)
    dNodes[sNodeName].y = (dNodes[sNodeName].level * 50)
}

罗曼

晕！

谢谢Limin对这个答案的评论！

我设置force.gravity(0)，然后在函数中添加了边界（.attr("cx/cy")）：nodetick()

function tick() {
    link
        .attr("x1", function(d) { return d.source.x; })
        .attr("y1", function(d) { return d.source.y; })
        .attr("x2", function(d) { return d.target.x; })
        .attr("y2", function(d) { return d.target.y; });

    node
        .attr("transform", function(d) { return "translate(" + d.x + "," + d.y + ")"; })
        .attr("cx", function(d) { return d.x = Math.max(8, Math.min(width - 8, d.x)); })
        .attr("cy", function(d) { return d.y = Math.max(100*d.level, Math.min(100*d.level, d.y)); });
}

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