Seaborn允许定义包含多种颜色的调色板,这对于具有多行的图表很有用。但是,将调色板设置为具有多种颜色的调色板时,仅使用前六种,之后颜色会循环使用,从而很难区分线条。可以通过显式调用调色板来覆盖它,但这并不方便。当定义了6种以上时,是否有办法强制Seaborn当前调色板不回收颜色?
例子:
from matplotlib import pyplot as plt
import pandas as pd
import seaborn as sb
# Define a palette with 8 colors
cmap = sb.blend_palette(["firebrick", "palegreen"], 8)
sb.palplot(cmap)
# Set the current palette to this; only 6 colors are used
sb.set_palette(cmap)
sb.palplot(sb.color_palette() )
df = pd.DataFrame({x:[x*10, x*10+5, x*10+10] for x in range(8)})
fig, (ax1, ax2) = plt.subplots(2,1,figsize=(4,6))
# Using the current palette, colors repeat
df.plot(ax=ax1)
ax1.legend(bbox_to_anchor=(1.2, 1))
# using the palette that defined the current palette, colors don't repeat
df.plot(ax=ax2, color=cmap)
ax2.legend(bbox_to_anchor=(1.2, 1)) ;
解决方案(由于使用@tcaswell作为指针):使用所有颜色显式设置调色板:
# Setting the palette using defaults only finds 6 colors
sb.set_palette(cmap)
sb.palplot(sb.color_palette() )
sb.palplot(sb.color_palette(n_colors=8) )
# but setting the number of colors explicitly allows it to use them all
sb.set_palette(cmap, n_colors=8)
# Even though unless you explicitly request all the colors it only shows 6
sb.palplot(sb.color_palette() )
sb.palplot(sb.color_palette(n_colors=8) )
# In a chart, the palette now has access to all 8
fig, ax1 = plt.subplots(1,1,figsize=(4,3))
df.plot(ax=ax1)
ax1.legend(bbox_to_anchor=(1.2, 1)) ;
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