这是创建表线程上的另一个错误1005，错误150。我见过很多，但没有一个能回答我的问题。

我在mysql工作台中有一个数据库，该数据库是前向设计的，并充满了数据。然后，从模型视图创建一个新表。然后，在此新表和数据库中的现有表之间添加一个：m关系。

最后，我尝试同步数据库。为创建两个新表而生成的代码是：

SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0;
SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0;
SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL,ALLOW_INVALID_DATES';

CREATE TABLE IF NOT EXISTS `mydb`.`SEntences` (
  `idSEntences` INT(11) NOT NULL,
  PRIMARY KEY (`idSEntences`))
ENGINE = InnoDB
DEFAULT CHARACTER SET = latin1
COLLATE = latin1_bin;

CREATE TABLE IF NOT EXISTS `mydb`.`Tips_has_SEntences` (
  `Tips_idTips` VARCHAR(45) NOT NULL,
  `SEntences_idSEntences` INT(11) NOT NULL,
  PRIMARY KEY (`Tips_idTips`, `SEntences_idSEntences`),
  INDEX `fk_Tips_has_SEntences_SEntences1_idx` (`SEntences_idSEntences` ASC),
  INDEX `fk_Tips_has_SEntences_Tips1_idx` (`Tips_idTips` ASC),
  CONSTRAINT `fk_Tips_has_SEntences_Tips1`
    FOREIGN KEY (`Tips_idTips`)
    REFERENCES `mydb`.`Tips` (`idTips`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION,
  CONSTRAINT `fk_Tips_has_SEntences_SEntences1`
    FOREIGN KEY (`SEntences_idSEntences`)
    REFERENCES `mydb`.`SEntences` (`idSEntences`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB
DEFAULT CHARACTER SET = latin1
COLLATE = latin1_bin;


SET SQL_MODE=@OLD_SQL_MODE;
SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS;
SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS;

我收到此日志错误：

Executing SQL script in server
ERROR: Error 1005: Can't create table 'mydb.Tips_has_SEntences' (errno: 150)


CREATE TABLE IF NOT EXISTS `mydb`.`Tips_has_SEntences` (
  `Tips_idTips` VARCHAR(45) NOT NULL,
  `SEntences_idSEntences` INT(11) NOT NULL,
  PRIMARY KEY (`Tips_idTips`, `SEntences_idSEntences`),
  INDEX `fk_Tips_has_SEntences_SEntences1_idx` (`SEntences_idSEntences` ASC),
  INDEX `fk_Tips_has_SEntences_Tips1_idx` (`Tips_idTips` ASC),
  CONSTRAINT `fk_Tips_has_SEntences_Tips1`
    FOREIGN KEY (`Tips_idTips`)
    REFERENCES `mydb`.`Tips` (`idTips`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION,
  CONSTRAINT `fk_Tips_has_SEntences_SEntences1`
    FOREIGN KEY (`SEntences_idSEntences`)
    REFERENCES `mydb`.`SEntences` (`idSEntences`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB
DEFAULT CHARACTER SET = latin1
COLLATE = latin1_bin

SQL script execution finished: statements: 3 succeeded, 1 failed

Fetching back view definitions in final form.
Nothing to fetch

使用SHOW ENGINE INNODB STATUS \ G命令从终端运行mysql，我从最近的外键错误字段获得以下输出：

------------------------
LATEST FOREIGN KEY ERROR
------------------------
141007 14:18:53 Error in foreign key constraint of table mydb/Tips_has_SEntences:

    FOREIGN KEY (`Tips_idTips`)
    REFERENCES `mydb`.`Tips` (`idTips`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION,
  CONSTRAINT `fk_Tips_has_SEntences_SEntences1`
    FOREIGN KEY (`SEntences_idSEntences`)
    REFERENCES `mydb`.`SEntences` (`idSEntences`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB
DEFAULT CHARACTER SET = latin1
COLLATE = latin1_bin:
Cannot find an index in the referenced table where the
referenced columns appear as the first columns, or column types
in the table and the referenced table do not match for constraint.
Note that the internal storage type of ENUM and SET changed in
tables created with >= InnoDB-4.1.12, and such columns in old tables
cannot be referenced by such columns in new tables.
See http://dev.mysql.com/doc/refman/5.5/en/innodb-foreign-key-constraints.html
for correct foreign key definition.

在研究了我的问题之后，我不知道出了什么问题。所有数据类型均相同，外键位于主键（其上具有主索引）等。我研究了此错误的各种堆栈溢出答案，并查看了此页面，并链接其中一个：MySQL错误号1005无法创建表'。\ mydb＃sql-328_45.frm'（errno：150）我已经尽力搜索了，但是答案仍然在那里。在这种情况下，很抱歉。

也许它与旧表（Tips）中已经有数据的事实有关。同步一个1：n关系，这在旧表（提示）中添加了一个外键，尽管很奇怪。如果数据是问题，那将行不通，正如我在这篇文章中发现的：如何向MySQL表添加外键？

另一方面，添加1：n关系（这需要将旧表的外键（提示）添加到新表）会产生相同的错误和日志（除了引用这样的表之外： 。\ mydb＃sql-328_45.frm'）。

我应该注意，这些问题对于我的任何旧表（数据库中已有数据的表）都会发生。另外，我相当确定在用数据填充数据库之后，在继续填充数据库之前以及尝试添加这些新表之前，我更新了mysql工作台。现在是第6版，可以在Linux的kubuntu中运行。

这里有什么问题，如何解决？是否走到了极端，例如导出数据库，删除和导入数据库？即使在这种情况下，我该怎么办？请记住，这是一个包含许多数据条目的数据库，大约100000。

如果您需要更多信息，我将在此处提供。

提示表创建代码：

SHOW CREATE TABLE mydb.Tips;

CREATE TABLE `Tips` (
  `idTips` varchar(45) CHARACTER SET latin1 NOT NULL,
  `like_count` int(10) unsigned DEFAULT NULL,
  `text` longtext CHARACTER SET latin1,
  `created_at` bigint(19) unsigned DEFAULT NULL,
  `url` varchar(100) CHARACTER SET latin1 DEFAULT NULL,
  `todo_count` bigint(19) unsigned DEFAULT NULL,
  `save_count` bigint(19) unsigned DEFAULT NULL,
  `Venues_idVenues` varchar(45) CHARACTER SET latin1 NOT NULL,
  PRIMARY KEY (`idTips`),
  KEY `fk_Tips_Venues1` (`Venues_idVenues`),
  CONSTRAINT `fk_Tips_Venues1` FOREIGN KEY (`Venues_idVenues`) REFERENCES `Venues` (`idVenues`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB DEFAULT CHARSET=latin1 COLLATE=latin1_bin