用两个不同的值对嵌套的php数组进行排序

user3508214 发表于 Dev

用户名

我想先按[artist] [0] [name]，然后按[datetime]对数组进行排序，所以最终得到类似

9/25 - Artist1
9/26 - Artist1
9/27 - Artist1
9/25 - Artist2
9/26 - Artist2
9/27 - Artist2
...

这就是我从提要中获取数据的方式：

Array
(
[0] => Array
    (
        [ticket_url] => ...
        [on_sale_datetime] => ...
        [ticket_status] => ...
        [url] => ...
        [venue] => Array
            (
                [longitude] => ...
                [region] => ...
                [city] => ...
                [url] => ...
                [country] => ...
                [id] => ...
                [latitude] => ...
                [name] => ...
            )

        [artists] => Array
            (
                [0] => Array
                    (
                        [mbid] => ...
                        [url] => ...
                        [name] => ...
                    )

            )

        [datetime] => ...
        [id] => ...
    )
)

我可以按[名称]进行排序，但无法弄清楚如何使[日期时间]与每个[名称]保持一致。这是我到目前为止的内容：

    $object = $x->eventSearch($artists, $location, null, "$today,$next_week", 1, 100);

    $array = objectToArray($object);

    usort($array, function($a, $b) {
        return strcmp($a['artists'][0]['name'], $b['artists'][0]['name']);
    });

    foreach ($array as $key => $val)
    {

        $main_artist = $val[artists][0][name];

        $dateofevent = date("m/d", strtotime($val[datetime]));
        $venue_city = $val[venue][city];
        $venue_region = $val[venue][region];
        $venue_name = $val[venue][name];
        ?>
        <tr>
            <td><?php echo $dateofevent; ?></td>
            <td><?php echo $main_artist; ?></td>
            <td><?php echo $venue_city . ", " . $venue_region; ?></td>
            <td><?php echo $venue_name; ?></td>
        </tr>
    <?php } ?>

任何见识将不胜感激。

萨米奇

请按照以下步骤进行操作，然后按歌手姓名和日期/时间排序。

usort($array, function($a, $b) {
    $s = strcmp($a['artists'][0]['name'], $b['artists'][0]['name']);
    if($s != 0 ) { return $s; }
    datetime_comparison_here(); // your example data is helpfully '...'
});

本文收集自互联网，转载请注明来源。

如有侵权，请联系[email protected] 删除。