我正在调试一个需要检查DNS查询的资源类是否为IN类型的应用程序。这是我发现的：
[6] pry(#<DNS::Server>)> resource_class
=> Resolv::DNS::Resource::IN::A
[7] pry(#<DNS::Server>)> resource_class.inspect
=> "Resolv::DNS::Resource::IN::A"
[8] pry(#<DNS::Server>)> resource_class.class.name
=> "Class"
[9] pry(#<DNS::Server>)> resource_class.kind_of? Class
=> true
[10] pry(#<DNS::Server>)> resource_class.kind_of? Resolv::DNS::Resource::IN::A
=> false
[11] pry(#<DNS::Server>)> resource_class.instance_of? Class
=> true
[12] pry(#<DNS::Server>)> resource_class.instance_of? Resolv::DNS::Resource::IN::A
=> false
[13] pry(#<DNS::Server>)> resource_class.is_a? Class
=> true
[14] pry(#<DNS::Server>)> resource_class.is_a? Resolv::DNS::Resource::IN::A
=> false
我试图检查使用resource_class.instance_of? Resolv::DNS::Resource::IN::A哪个不起作用。我该如何检查？
你resource_class是一堂课。它不是的实例Resolv::DNS::Resource::IN::A; 它是 Resolv::DNS::Resource::IN::A。因此，简单的比较就足够了：
resource_class == Resolv::DNS::Resource::IN::A
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我来说两句