假设我正在查看特定日期：
from datetime import date, timedelta
days_to_substract = 65
my_date = date.today()-timedelta(days=days_to_subtract)
我如何找到：
Monday之前的权利my_date（如果my_date不是一个星期一）Monday到my_date有没有办法舍入日期datetime？
你可以使用dateutil
from datetime import *
from dateutil.relativedelta import *
days_to_substract = 64
my_date = (date.today()-timedelta(days=days_to_substract))
next=my_date+relativedelta(weekday=MO)
previous=my_date+relativedelta(weekday=MO(-1))
print ('mydate is %s' %my_date)
print ('next monday is %s' %next)
print ('previous monday is %s' %previous)
diff1=my_date-previous
diff2=next-my_date
if diff2<diff1:
print ('Closest monday is %s' %next)
else:
print ('Closest monday is %s' %previous)
将输出：
mydate is 2014-01-21
next monday is 2014-01-27
previous monday is 2014-01-20
Closest monday is 2014-01-20
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