解析短信的最佳方法是什么

我正在开发一个用于将短信解析为要存储在sqlite db中的字符串的应用程序。

这是短信外观的示例。通话费样品。

Airtime payment made for UGX5,000 to KKL(0909xxxx).
Your Balance is UGX10,000.
Thank you for using KKL MobileMoney.

手机存款样本

You have received UGX100,000 from 09006700. Reason:J.
Your balance is UGX170,000.

移动汇款示例

You have sent UGX10,000 to 08970000.
Reason:j.
Your balance is UGX120,000.
Thank you for using KKL MobileMoney.

我感兴趣的是：-发送/接收/支付的金额。-从/发送/付款的号码。-原因-平衡。

到目前为止，我已经尝试使用split函数。

我使用的是字符串令牌的数组索引，但是在某些字符串上我得到了索引出界异常，但在某些字符串上却起作用了。

这是我到目前为止的代码...但是工作不一致！

if (str.startsWith(RECEIVED))
            {
                // for mm deposit
                Log.e("msg", str);
                String delimeter="[ .]+";
                String[] tokens= str.split(delimeter);
                for (int i=0;i < tokens.length;i++)
                {
                    Log.e("Test",tokens[i]);    
                    }                       
                    String amount =tokens[3];
                    String reason =tokens[6].trim();            
                    String number=tokens[5];
                    String balance=tokens[11];              
                    Log.e("Amount",amount);
                    Log.e("reasons",reason);
                    Log.e("number",number);
                    Log.e("balance",balance);
                    String type="Deposit";
                    db.addrecord(amount, type, reason, number, balance);
                    db.close();
            }
            else if(str.startsWith(SEND))
            {   
                // for sent sms
                Log.e("msg", str);           
            String delimeter="[ .]+";
            String[] tokens= str.split(delimeter);
            for (int i=0;i < tokens.length;i++)
            {
                Log.e("Test",tokens[i]);    
                }                   
                String amount =tokens[3];
                String reason =tokens[6].trim();                
                String number=tokens[5];
                String balance=tokens[11];                          
                Log.e("Amount",amount);
                Log.e("reasons",reason);
                Log.e("number",number);
                Log.e("balance",balance);               
                String type="Payment";
                db.addrecord(amount, type, reason, number, balance);
                db.close();
            }

        else if(str.startsWith(AIRTIMEPAYMENT))
        {       // for airtime sms
            Log.e("msg", str);
            String delimeter="[ .]+";
            String[] tokens= str.split(delimeter);
            for (int i=0;i < tokens.length;i++)
            {
                Log.e("Test",tokens[i]);    
                }                       
                String amount =tokens[4];
                String reason =tokens[0]+ " "+ tokens[1];   
                String number=tokens[7];
                String balance=tokens[11];              
                Log.e("Amount",amount);
                Log.e("reasons",reason);
                Log.e("number",number);
                Log.e("balance",balance);
                String type="Air Time ";
                db.addrecord(amount, type, reason, number, balance);
                db.close();
        }

关于如何最好地处理解析的任何提示/建议？

我是Java / Android初学者！

罗纳德

这是我所做的编辑

private Map<String, String> parseSms(String s){
    Map<String, String> ret = new HashMap<String, String>();
    s = s.replace("\n", "");
    StringTokenizer t = new StringTokenizer(s, ".");
    while (t.hasMoreTokens()){
        String b = t.nextToken().trim();
        if (b.startsWith("You have sent") ||(b.startsWith("You have received"))){
            String type = getType(b);
            String parsed = parseAmount(b);
            String number = parseNumber(b);
            ret.put("amount", parsed);
            ret.put("number", number);
            ret.put("type", type);
        }else if(b.startsWith("Your")){//balance
            String parsed = parseAmount(b);
            ret.put("balance", parsed);
        }else if (b.startsWith("Reason")){

            ret.put("reason", b.toString());
        }
        else if( b.startsWith("Airtime"))
        {
              String type = getType(b);
              String parsed = parseAmount(b);
              String number = parseNumber(b);
              ret.put("amount", parsed);
              ret.put("number", number);
              ret.put("reason", "Air Time Payment");
              ret.put("type", type);
          }else if(b.startsWith("Your")){//balance
            String parsed = parseAmount(b);
            ret.put("balance", parsed);

        }


    }

    return ret;
}

它解决了问题。