多个INNER JOIN子查询sql

我有下面的查询，该查询来自于mysql中连续记录的项目数，该计数计算一个学生在一堂课中连续出现/缺席的次数。

    SELECT
        classlist.studentid,
        student.name,
        classStatus.name status,
        COUNT(*) presentcnt
    FROM
        classlist 
        INNER JOIN student ON classlist.studentid=student.id
        INNER JOIN classstatus ON classlist.presentid=classstatus.id
        INNER JOIN (
            SELECT
                studentid,
                max(CASE WHEN presentid=0 THEN id END)  max_0,
                max(CASE WHEN presentid=1 THEN id END)  max_1
            FROM classlist
            GROUP BY studentid
        ) s
        ON coalesce(classlist.id>least(max_0,max_1) AND classlist.id<=greatest(max_0,max_1),1) AND s.studentid=classlist.studentid
    GROUP BY classlist.studentid

这按预期工作，

    STUDENTID   NAME    STATUS  PRESENTCNT
    111         John    Present     1
    222         Kate    Absent      2
    333         Matt    Present     5

我想扩展查询，以便有一个列显示学生是否参加了课堂。

如果我运行独立查询，则会得到想要的结果

    SELECT
        classlist.studentid,
        student.name,
        participatedStatus.name status,
        COUNT(*) participatedcnt
    FROM
        classlist 
        INNER JOIN student ON classlist.studentid=student.id
        INNER JOIN participatedStatus ON classlist.participatedid=participatedStatus.id
        INNER JOIN (
            SELECT
                studentid,
                max(CASE WHEN participatedid=0 THEN id END)  max_0,
                max(CASE WHEN participatedid=1 THEN id END)  max_1
            FROM classlist
            group by studentid
        ) s
        ON coalesce(classlist.id>least(max_0,max_1) 
        AND classlist.id<=greatest(max_0,max_1),1)
        AND s.studentid=classlist.studentid
    group by classlist.studentid

    STUDENTID   NAME    STATUS  PARTICIPATEDCNT
    111         John    Yes     1
    222         Kate    No      2
    333         Matt    Yes     2

但是我想将它们合并到一个查询中，所以我得到

    STUDENTID   NAME    STATUS  PRESENTCNT  STATUS2     PARTICIPATEDCNT
    111         John    Present     1       Yes         1
    222         Kate    Absent      2       No          2
    333         Matt    Present     5       Yes         2

我在选择count *时如何实现这一目标感到困惑，我该如何实现呢？

我正在使用的数据样本在这个小提琴中和下面

    CREATE TABLE classlist
        (`id` int, `studentid` int, `subjectid` int, `presentid` int, `participatedid` int);

    CREATE TABLE student
        (`id` int, `name` varchar(4));

    CREATE TABLE subject
        (`id` int, `name` varchar(4));

    CREATE TABLE classStatus
        (`id` int, `name` varchar(8));

    CREATE TABLE participatedStatus
        (`id` int, `name` varchar(8));

    INSERT INTO classlist   (`id`, `studentid`, `subjectid`, `presentid`, `participatedid`)
    VALUES  (1, 111, 1, 1, 0),  (2, 222, 3, 0, 0),  (3, 333, 2, 1, 0),  (4, 111, 4, 0, 0),  (5, 111, 1, 1, 0),  (6, 222, 3, 0, 0),  (7, 333, 2, 1, 1),  (8, 111, 4, 0, 0),  (9, 111, 4, 0, 0),  (10, 111, 4, 0, 0), (11, 111, 1, 1, 1), (12, 333, 3, 1, 0), (13, 333, 2, 1, 1), (14, 333, 3, 1, 1);

    INSERT INTO student (`id`, `name`)
    VALUES  (111, 'John'),(222, 'Kate'),(333, 'Matt');

    INSERT INTO subject (`id`, `name`)
    VALUES  (1, 'MATH'),(2, 'ENG'),(3, 'SCI'),(4, 'GEO');

    INSERT INTO classStatus (`id`, `name`)
    VALUES  (0, 'Absent'),  (1, 'Present');

    INSERT INTO participatedStatus  (`id`, `name`)
    VALUES  (0, 'No'),(1, 'Yes');