Java：在字符串中查找字符串

J Code 发表于 Dev

J代码

我正在尝试制作一种可以检测Java语法并突出显示该代码的系统。但是，我似乎在查找字符串中的字符串时遇到麻烦。

这是我到目前为止所拥有的：

import java.util.Scanner;

public class Client {

    private static String[] javaKeywords = {
        "abstract", "assert", "boolean", "break", "byte", "case", "catch", "char", "class", "const", "continue",
        "default", "do", "double", "else", "enum", "extends", "final", "finnaly", "float", "for", "goto", "if",
        "implements", "import", "instanceof", "int", "interface", "long", "native", "new", "package", "primitve",
        "private", "protected", "public", "return", "short", "static", "strictfp", "super", "switch", "synchronized", 
        "this", "throw", "throws", "transient", "try", "void", "volatile", "while"
    };

    private static String[] javaSyntax = {
        "++", "--", "~", "!", "*", "/", "%", "+", "-", " <<", ">>", ">>>", "<", ">", "<=", ">=", "==", "!=", "&",
        "^", "|", "&&", "||", "?", ":", "=", "+=", "-=", "/=", "%=", "&=", "^=", "|=", "<<=", ">>=", ">>>="
    };

    private static Scanner scanner = new Scanner(System.in);
    private static StringBuilder builder = new StringBuilder();

    public static void main(String args[]) {

        String input;

        while(!(input = scanner.nextLine()).toLowerCase().contains("exit")) {

            switch(input.toLowerCase()) {
                case "print":
                    System.out.println(builder.toString());
                    continue;

                case "clear":
                    builder = new StringBuilder();
                    continue;
            }

            builder.append(input + "\n");
            codeWrap(builder.toString());

        }

   }

    private static void codeWrap(String code) {
        int A4I = 0, position; // A4I = Account for insert length
        for(String keyword: javaKeywords) {

            if((position = findInString(code, keyword)) != -1) {
                builder.insert(position + A4I, "[code]");
                A4I += 6;
                builder.insert(position + keyword.length() + A4I, "[/code]");
                A4I += 7;
           }

        }
    }

    private static int findInString(String string, String keyword) {
        for(int index = 0, keywordIndex = 0; index < string.length(); index++) {

            keywordIndex = (string.charAt(index) == keyword.charAt(keywordIndex)) ? ++keywordIndex : 0;

            if(keywordIndex == keyword.length()) return ((index + 1) - keyword.length());

        }
        return -1;
    }

}

这在大多数情况下都有效，但是，如果您尝试用两个关键字包装一个句子，则如果关键字b在javaKeywords数组中的关键字a之前，它将返回一个奇怪的结果。

例如：在b（while）之前有a（抽象）的结果

abstract while
print
[code]abstract[/code] [code]while[/code]

b（while）在a（abstract）之前的结果

while abstract
print
while [code]a[code]bstra[/code]ct[/code]

ug_

你A4I不需要在这种情况下变量，并导致你做出那些已经计算偏移。请注意以下几点：

while abstract
>loop finds 'abstract' at position 6
while [code]abstract[/code]
>A4I is now making all offsets +13
>loop finds 'while' found at position 0
>you add that +13 offset to the insert making it drop right in the middle of the abstract

您还将向codeWrap方法中传递2个字符串，因为字符串是不可更改的，因此您要在字符串中搜索索引，然后在其他字符串上使用它。您还会在程序中发现其他一些奇怪的问题，但这应该可以解决您的直接问题

private static void codeWrap() {
    int position;
    for(String keyword: javaKeywords) {

        if((position = findInString(builder.toString(), keyword)) != -1) {
            builder.insert(position, "[code]");
            builder.insert(position + keyword.length()+6, "[/code]");
       }

    }
}

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