使用列表获取平均值

MikeinFl 发表于 Dev

迈克宁

该程序应要求用户输入12个月的每月降雨量，计算并合计该年的降雨量，平均每月降雨量以及数量最高和最低的月份。

我可以要求输入，给出每年的总数和每月的平均值，但是我觉得程序的输入部分应该以某种方式削减，它看起来太大而笨重，我还不太清楚如何获得高/低平均值。任何帮助将非常感激。提前致谢。

def main():
    jan = int(input('Enter Rainfall For January: '))
    feb = int(input('Enter Rainfall for February: '))
    mar = int(input('Enter Rainfall For March: '))
    april = int(input('Enter Rainfall For April: '))
    may = int(input('Enter Rainfall For May: '))
    june = int(input('Enter Rainfall For June: '))
    jul = int(input('Enter Rainfall For July: '))
    aug = int(input('Enter Rainfall For August: '))
    sept = int(input('Enter Rainfall For September: '))
    oct = int(input('Enter Rainfall For October: '))
    nov = int(input('Enter Rainfall For November: '))
    dec = int(input('Enter Rainfall For Deceember: '))
    totalyear = jan + feb + mar + april + may + june + jul + aug + sept + oct + nov + dec
    print('The total for the year is: ',totalyear)
    avg = jan + feb + mar + april + may + june + jul + aug + sept + oct + nov + dec / 12
    print('The average monthly rainfall is: ',avg)
main()

超本能

您可以使用列表和循环。:)

def main():
    months = ["Jan","Feb" .... ,"Dec"]
    rain = []
    for month in months:
        rain.append(int(input("Enter .. for" + month)))
    print("Total", sum(rain))
    print("Average", sum(rain)/float(len(rain)))

同样，对于最大值和最小值，可以使用max(rain)和min(rain)。

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