失败1：语法错误

Evana Hill 发表于 Dev

伊凡娜山

我是SQLite的新手。我正在尝试在Android中使用SQLite。但是我在运行它时遇到了这种错误。

错误：

准备时，0x14d2c8出现故障1（在“ tableuserInfoTable”附近：语法错误）'create tableuserInfoTable(_id integer primary key name text not nullemailtext not nullpasswordtext not nulltimetext not null);'。

码：

import android.content.Context;
import android.database.sqlite.SQLiteDatabase;
import android.database.sqlite.SQLiteOpenHelper;
import android.util.Log;

public class DBHelper extends SQLiteOpenHelper {
    public static final String DATABASE_NAME="data";
    public static final int DATABASE_VERSION=1;

    public static final String USER_TABLE="userTable";
    public static final String C_ID="_id";
    public static final String USER="name";
    public static final String EMAIL="email";
    public static final String PASSWORD="password";
    public static final String TIME="time";

    public final String createDB="create table"+USER_TABLE+"("+C_ID+" integer primary key "
                             +USER+" text not null"  +EMAIL+ "text not null" +PASSWORD+ "text not null" 
                             +TIME+ "text not null);";

    public DBHelper(Context context)
    {
        super(context,DATABASE_NAME, null, DATABASE_VERSION);
        // TODO Auto-generated constructor stub
    }

    @Override
    public void onCreate(SQLiteDatabase db) {
        // TODO Auto-generated method stub
        db.execSQL(createDB);
    }


@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
    // TODO Auto-generated method stub
    if (newVersion > oldVersion) {
        Log.w("MyAppTag","Updating database from version " + oldVersion + " to "
                + newVersion + " .Existing data will be lost.");
  db.execSQL("drop table if exists"+USER_TABLE);
  onCreate(db);
}
}  
 }

我几乎遍历了SO中的每个示例，但我无法弄清楚。谢谢

菲利普·席尔瓦（Filipe Silva）

尝试这个

public final String createDB="create table "+USER_TABLE+"("
                         +C_ID+" integer primary key, "
                         +USER+" text not null,"  
                         +EMAIL+ " text not null," 
                         +PASSWORD+ " text not null," 
                         +TIME+ " text not null);";

几个错误：-您缺少table和tableName之间的空格；-您缺少列末尾的逗号，-您还缺少列名与数据类型之间的空格：

您应该始终记录查询并尝试直接在数据库中运行它。错误将很快被清除。

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