我正在尝试从输入文件中获取字符，但是我真的无法使其正常工作，有人可以帮助我解决这个问题吗？我事先为格式表示歉意，这让我感到困惑。
open_input_and_output_file基本上检查您是否可以打开文件，在OTP中，我试图将每个字符从一个文件传输到另一个文件。由于无法正常工作，我首先尝试在控制台应用程序中显示这些字符，但这也不起作用。
任何帮助将不胜感激，我希望所提供的信息足够。
bool open_input_and_output_file(ifstream& infile, ofstream& outfile)
{
//Precondition: True
assert(true);
//Postcondition: Inputfile and outputfile have either been opened succesfully or you have been notified of it not opening succesfully.
string inputfile;
string outputfile;
cout<<"\nPlease enter an input-file name (no spaces): ";
cin>>inputfile;
cout<<"NOTE: Input-file name and output-file name can NOT be the same!"<<endl;
cout<<"Please enter an output-file name (no spaces): ";
cin>>outputfile;
if(inputfile != outputfile)
{
cout<<"Input-file name and output-file name are not the same! Good job on reading!"<<endl;
ifstream infile(inputfile.c_str());
if(infile)
cout<<"Input-file: "<<inputfile<<" was opened succesfully!"<<endl;
if(!infile)
cout<<"Inputfile: "<<inputfile<<" could not be opened!"<<endl;
ofstream outfile(outputfile.c_str());
if(outfile)
cout<<"Output-file: "<<outputfile<<" was opened succesfully!"<<endl;
if(!outfile)
cout<<"Outputfile: "<<outputfile<<" could not be opened!"<<endl;
}
else
{
cout<<"Input-file name and output-file name are the same!"<<endl;
cout<<"Opening has failed!"<<endl;
}
return 0;
}
void OTP(ifstream& infile, ofstream& outfile)
{
int choice;
char character;
unsigned int r;
srand(r);
cout<<"\nPlease enter 0 to encrypt or 1 to decrypt: ";
cin>>choice;
if(open_input_and_output_file(infile,outfile))
{
infile.get(character);
cout<<character;
}
}
我会说错误在这里
cout<<"Input-file name and output-file name are not the same! Good job on reading!"<<endl;
ifstream infile(inputfile.c_str());
应该
cout<<"Input-file name and output-file name are not the same! Good job on reading!"<<endl;
infile.open(inputfile.c_str());
您用outfile犯了同样的错误。
ofstream outfile(outputfile.c_str());
应该
outfile.open(outputfile.c_str());
您将infile和outfile作为参数传递给open_input_and_output_file函数，但随后在函数内部再次声明它们。因此，当您打开文件时，您不使用传递给的流open_input_and_output_file，而是使用该函数本地的流。溪流通过以open_input_and_output_file保持封闭。
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我来说两句