我有这些查询：
select b.type,b.name,a.name_b,a.start_time
from runinfo a left JOIN definition b
on a.sched_table=b.parent_table
and a.name_b=b.name
where sched_table not like 'PLAN'
and to_char(start_time,'YYYYMMDD') = to_char(current_date-1,'YYYYMMDD')
order by start_time desc;
表是：
DEFINITION
----------
TYPE: COMMAND
NAME: DAVE
.........
RUNINFO
-------
START_TIME: 2019/08/15 23:59
NAME_B: DAVE
.........
START_TIME: 2019/08/15 23:58
NAME_B: DAVE
........
我得到重复的行，我听不懂：
TYPE NAME START_TIME NAME_B
COMMAND DAVE 2019/08/15 23:59 DAVE
COMMAND DAVE 2019/08/15 23:59 DAVE
COMMAND DAVE 2019/08/15 23:58 DAVE
COMMAND DAVE 2019/08/15 23:58 DAVE
为什么每条记录都有两行？
感谢和抱歉我的英语！
我想你需要一个INNER JOIN而不是LEFT JOIN-
SELECT DISTINCT b.type,b.name,a.name_b,a.start_time
FROM runinfo a
INNER JOIN definition b ON a.sched_table=b.parent_table
AND a.name_b=b.name
WHERE sched_table NOT LIKE '%PLAN%'
AND TO_CHAR(start_time,'YYYYMMDD') = TO_CHAR(current_date-1,'YYYYMMDD')
ORDER BY start_time DESC;
另外，我还更新了您的Like谓词。
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我来说两句