我有一个二进制数向量。我知道每组对象的连续长度;如何根据该信息拆分(无for循环)?
x = c("1","0","1","0","0","0","0","0","1")
.length = c(group1 = 2,group2=4, group3=3)
x
是我需要拆分的二进制数向量。.length
是我得到的信息。.length
本质上告诉我第一组有2个元素,它们是前两个元素1,0
。第二组具有4
元素,并包含在组1的数字之后的4个数字1,0,0,0
,等等。
有没有办法将其拆分并将拆分后的项目返回到列表中?
丑陋的方法是通过for循环跟踪当前的累积量,但是我正在寻找一种更优雅的方法(如果有)。
您可以使用rep
设置拆分变量,使用split
x = c("1","0","1","0","0","0","0","0","1")
.length = c(group1 = 2,group2=4, group3=3)
split(x, rep.int(seq_along(.length), .length))
# $`1`
# [1] "1" "0"
#
# $`2`
# [1] "1" "0" "0" "0"
#
# $`3`
# [1] "0" "0" "1"
如果要将组名带到拆分列表,则可以更改rep
以复制名称
split(x, rep.int(names(.length), .length))
# $group1
# [1] "1" "0"
#
# $group2
# [1] "1" "0" "0" "0"
#
# $group3
# [1] "0" "0" "1"
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