将字符串拆分为向量c ++

caesar 发表于 Dev

凯撒

我编写了一个简单的代码，将字符串从每个“ /”中拆分出来并存储为向量。我的字符串可能以/开头，definetelly将以/结尾。例如，如果我的字符串是：

string="/home/desktop/test/" 
I want to <"/","home","desktop","test"> and another example

string="../folder1/folder2/../pic.pdf/" 
I want to store <"..","folder1","folder2","..","pic.pdf"

但是，我的代码为我<" ","home","desktop","test"," ">提供了第一个示例和<"..","folder1","folder2","..","pic.pdf"," ">第二个示例

有没有人可以帮助我？这是我的代码：

#include <iostream>
#include <vector>
#include <string>
using namespace std;
int main()
{
    string strLine("/cd/desktop/../test/");
    string strTempString;
    vector<int> splitIndices;
    vector<string> splitLine;
    int nCharIndex = 0;
    int nLineSize = strLine.size();

    // find indices
    for(int i = 0; i < nLineSize; i++)
    {
        if(strLine[i] == '/')
            splitIndices.push_back(i);
    }
    splitIndices.push_back(nLineSize); // end index

    // fill split lines
    for(int i = 0; i < (int)splitIndices.size(); i++)
    {
        strTempString = strLine.substr(nCharIndex, (splitIndices[i] - nCharIndex));
        splitLine.push_back(strTempString);
        cout << strTempString << endl;
        nCharIndex = splitIndices[i] + 1;
    }


}

erosenin

在代码中应该做的一些事情可以解决这个问题，为此可能会有一个更好，更优雅的解决方案。

#include <iostream>
#include <vector>
#include <string>
using namespace std;
int main()
{
    string strLine("/cd/desktop/../test/");
    string strTempString;
    vector<int> splitIndices;
    vector<string> splitLine;
    int nCharIndex = 0;
    int nLineSize = strLine.size();

    // find indices
    if(nLineSize!=0 && strLine[0]=='/')
    {
         splitLine.push_back(strLine.substr(0,1));
         nCharIndex++;
    }

    for(int i = 1; i < nLineSize; i++)
    {
        if(strLine[i] == '/')
            splitIndices.push_back(i);
    }

    // fill split lines
    for(int i = 0; i <int(splitIndices.size()); i++)
    {
        strTempString = strLine.substr(nCharIndex, (splitIndices[i] - nCharIndex));
        splitLine.push_back(strTempString);
        nCharIndex = splitIndices[i] + 1;
    }        
}

编辑：稍微清除了代码，您现在可以删除添加最后一个索引部分。

编辑2：

一个可能更美观的解决方案可能是删除ncharcounter并为此使用拆分索引。如果第一个字符不是（'/'），则可以将第一个值存储为'-1'；如果不是，则可以将其存储为（'0'）。

    string strLine("/cd/desktop/../test/");
    string strTempString;
    vector<int> splitIndices;
    vector<string> splitLine;
    int nLineSize = strLine.size();

    // find indices
    splitIndices.push_back(-1);
    if(nLineSize!=0 && strLine[0]=='/')
    {
         splitLine.push_back(strLine.substr(0,1));
         splitIndices[0]=0;
    }             
    for(int i = 1; i < nLineSize; i++)
    {
        if(strLine[i] == '/')
            splitIndices.push_back(i);
    }

    // fill split lines
    for(int i = 1; i <int(splitIndices.size()); i++)
    {
        strTempString = strLine.substr(splitIndices[i-1]+1, (splitIndices[i] - (splitIndices[i-1]+1) ));
        splitLine.push_back(strTempString);
    }