我的完整查询是：
$sql = "SELECT vehicle_id, fuel_type, gearbox_type, door_type, engine_package_name, FORMAT(engine_cap, 1)engine_cap, engine_power, FORMAT(fuel_cons, 1)fuel_cons, FORMAT(std_price, 0)std_price
FROM vehicle
WHERE model_id = '$model_id'
AND fuel_type IN ('$fuel_type1', '$fuel_type2', '$fuel_type3', '$fuel_type4') AND gearbox_type IN( '$gearbox_type1', '$gearbox_type2', '$gearbox_type3', '$gearbox_type4') AND door_type IN ('$door_type1', '$door_type2', '$door_type3', '$door_type4')" ;
如果$fuel_type1等于零，我想跳过下面显示的查询部分。
AND fuel_type IN ('$fuel_type1', '$fuel_type2', '$fuel_type3', '$fuel_type4')
我试过了
$sql = "SELECT vehicle_id, fuel_type, gearbox_type, door_type, engine_package_name, FORMAT(engine_cap, 1)engine_cap, engine_power, FORMAT(fuel_cons, 1)fuel_cons, FORMAT(std_price, 0)std_price
FROM vehicle
WHERE model_id = '$model_id' ";
if($fuel_type1 != 0)
{
$sql += “ AND fuel_type IN ('$fuel_type1', '$fuel_type2', '$fuel_type3', '$fuel_type4')”;
}
没有用。
我也试过
$sql = "SELECT vehicle_id, fuel_type, gearbox_type, door_type, engine_package_name, FORMAT(engine_cap, 1)engine_cap, engine_power, FORMAT(fuel_cons, 1)fuel_cons, FORMAT(std_price, 0)std_price
FROM vehicle
WHERE model_id='$model_id’
AND IF($fuel_type1 <> 0,'fuel_type','0') IN ('$fuel_type1', '$fuel_type2', '$fuel_type3', '$fuel_type4’)";
没有用:((
任何帮助将不胜感激。
问题出在您的串联过程中
在 PHP 中应该 ba do t.来连接而不是+签名
if($fuel_type1 != 0)
{
$sql .= “ AND fuel_type IN ('$fuel_type1', '$fuel_type2', '$fuel_type3', '$fuel_type4')”;
}
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