我想使用参数«returnUrl»的倍数来检索url中的一些参数。
例子:
HTTPS://force.com?positionId=a0w0X000007HjBuQAK&lang=fr&mediaChannel=a0o0X00000EGQ5TQAX&returnUrl=https%253A%2F%2force.com%2Fcxsrec__cxsSearchDetail%3Fid%3Da0w0X000007HjBuQAK%26lang%3Dfr%26mediaChannel%3Da0o0X00000EGQ5TQAX%26returnUrl%3Dhttps%253A%2F%2force.com%2Fcxsrec__cxsSearch%253Flang%253Dfr%2526mediaChannel%253Da0o0X00000EGQ5TQA%2526 site%253DFrance%2526hcFilter%253Da0Z0X00000XiFF3UAN%252Ca0Z0X00000XiUqTUAV%2526orderBy%253DPosition_name__c%2526orderDir%253Dasc%2526mediaChannel%253Da0o0X00000EGQ5TQAX%26lang%3Dfr%26mediaChannel%3Da0o0X00000EGQ5TQAX’
?... returnUrl %3Dhttps%253A%2F%2force.com%2Fcxsrec__cxsSearch%253Flang%253Dfr%2526mediaChannel%253Da0o0X00000EGQ5TQA%2526站点%253DFrance%2526hcFilter...
我想获取参数site的值。
我尝试使用decodeURI函数,然后使用searchParams.get("site")但decodeURI它没有在returnUrl之后解码参数。
是否有另一个功能可以做到这一点?
我之前site
在 URL 中删除了一个空格:
const url1 = new URL('https://force.com?positionId=a0w0X000007HjBuQAK&lang=fr&mediaChannel=a0o0X00000EGQ5TQAX&returnUrl=https%253A%2F%2force.com%2Fcxsrec__cxsSearchDetail%3Fid%3Da0w0X000007HjBuQAK%26lang%3Dfr%26mediaChannel%3Da0o0X00000EGQ5TQAX%26returnUrl%3Dhttps%253A%2F%2force.com%2Fcxsrec__cxsSearch%253Flang%253Dfr%2526mediaChannel%253Da0o0X00000EGQ5TQA%2526site%253DFrance%2526hcFilter%253Da0Z0X00000XiFF3UAN%252Ca0Z0X00000XiUqTUAV%2526orderBy%253DPosition_name__c%2526orderDir%253Dasc%2526mediaChannel%253Da0o0X00000EGQ5TQAX%26lang%3Dfr%26mediaChannel%3Da0o0X00000EGQ5TQAX');
const params1 = new URLSearchParams(url1.search);
const returnUrl = params1.get('returnUrl');
const url2 = new URL(decodeURIComponent(returnUrl));
const params2 = new URLSearchParams(url2.search);
const site = params2.get('site');
console.log(site);
查看描述中的一些细节encodeURIComponent()
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