循环数学方程

debugcn 发表于 Dev

阿维齐亚

所以我正在尝试制作一个像收银员这样的程序，该程序不断增加取决于用户购买产品的数量，但我的程序不会增加价值，但它会不断取代它

班级：

public class Class {
    private double drink, pdrink;
                public void SetDrink (double drink)
                {
                    this.drink = drink;
                }
                public void SetPDrink (double pdrink)
                {
                    this.pdrink = pdrink;
                }

            public double getDrink()
            {
                if (drink==1)
                    drink=500;
                else if (drink==2)
                    drink=1000;
                else if (drink==3)
                    drink=3000;
                else
                    drink=0;


                return drink;
            }


    public double getPDrink()
            {
    double total = getDrink();
            return total;
        }
}

主要类：

import java.util.Scanner;
/**
 *
 * 
 */
public class MainClass {

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {
        char ch = 0;
            char mi = 0;

    Scanner Class = new Scanner (System.in);
    Class p = new Class();
            int choice;
            char repeat = 'y';
            char drink = 'y' ;


            do {
    System.out.println("do you want to buy drinks?");
    System.out.println("1. A (500)");
    System.out.println("2. B (1000)");
    System.out.println("3. C (1500)");
    System.out.println("0 to not choose");
    System.out.println("Please choose you drink");

    p.SetDrink(Class.nextDouble());

    System.out.println("do you want to buy more?");

    mi = Class.next().charAt(0);

} while (mi == 'y');
    System.out.println("total= "+p.getDrink());
}
    }

我正在考虑使用“do while”，但我不确定该怎么做

编辑：我正在使用 oop，我正在尝试在课堂上使用开关，但它没有用

dkb

我正在使用 Scanner，您可以使用任何其他库从控制台读取输入。没有固定您的业务逻辑，例如打印“总”值。

    char mi;
    Scanner sc = new Scanner(System.in);
    double total = 0.0;
    do {
        System.out.println("do you want to buy drinks?");
        System.out.println("1. A (500)");
        System.out.println("2. B (1000)");
        System.out.println("3. C (1500)");
        System.out.println("0 to not choose");
        System.out.println("Please choose you drink");
        //p.SetDrink(sc.nextDouble()); // not working unknown p in OP, so commented
        char drink = sc.next().charAt(0);
        System.out.println(drink); // just printing user's choice for drink
        switch (drink) {
                case 'A':
                    total += 500;
                    break;
                case 'B':
                    total += 1000;
                    break;
                case 'C':
                    total += 1500;
                    break;
                default:
                    total += 0;
            }

        System.out.println("do you want to buy more?");

        mi = sc.next().charAt(0);
    } while (mi=='y');
    System.out.println("total : " + total);

输出：

do you want to buy drinks?
1. A (500)
2. B (1000)
3. C (1500)
0 to not choose
Please choose you drink
C
C
do you want to buy more?
y
do you want to buy drinks?
1. A (500)
2. B (1000)
3. C (1500)
0 to not choose
Please choose you drink
A
A
do you want to buy more?
n
total : 2000.0

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