错误：非静态成员函数 C++ 的无效使用

debugcn 发表于 Dev

用户3798451

我有两个要链调用的类（主 -> 执行 -> 计算）。但是，问题是当我使用：

&calculate::addition;

即使编译器没有返回任何错误，也不会调用加法。如果我尝试删除对

calculate::addition;

编译器返回错误

error: invalid use of non-static member function ‘void calculate::addition(double&, double, double)’
     case 'a' : *calculate::addition; break;
                            ^~~~~~~~

尝试在 void 之前使用 static ，结果与使用引用相同。

#include <iostream>

class execute{
   public:
     void exec(char);
}jalan;
class calculate {
   public:
     void addition(double&, double, double);
     void substraction(double&, double, double);
     void multiply(double&, double, double);
     void division(double&, double, double);
};
int main(void){
static double a, b;
static double result;
  std::cout << "Type a, b, c, or d" << std::endl;
  std::cout << "a. Addition\nb. Substraction\nc. Multiply\nd. Division" << std::endl;
  std::cout << "Your Input: ";
      static char option;
    option = getchar();
                std::cout << "First value: ";
                std::cin >> a;
                std::cout << "Next value: ";
                std::cin >> b;
      jalan.exec(option);
    std::cout << result << std::endl;
                return 0;
}
void execute::exec (char option){
    switch(option){
                                case 'a' : &calculate::addition; break;
                                case 'b' : &calculate::substraction; break;
                case 'c' : &calculate::multiply; break;
                case 'd' : &calculate::division; break;
        }   
}
void calculate::addition(double& result, double a, double b){
            result = a+b;   
}
void calculate::substraction(double& result, double a, double b){
            result = a-b;   
}
void calculate::multiply(double& result, double a, double b){
            result = a*b;   
}
void calculate::division(double& result, double a, double b){
            result = a/b;   
}

用户32434999

您的代码中有几个问题。开始吧：

error: invalid use of non-static member function ‘void calculate::addition(double&, double, double)’
 case 'a' : *calculate::addition; break;

这意味着您必须创建一个计算实例或使用静态标记该方法，例如 static void addition(double&, double, double);

所以把你的班级改成

class calculate {
public:
    static void addition(double&, double, double);
    static void substraction(double&, double, double);
    static void multiply(double&, double, double);
    static void division(double&, double, double);
};

下一个问题是，在您的 switch 语句中，您只创建指向函数的指针

void execute::exec (char option){
    switch(option){
    case 'a' : &calculate::addition; break;
    case 'b' : &calculate::substraction; break;
    case 'c' : &calculate::multiply; break;
    case 'd' : &calculate::division; break;
    }   
}

这永远不会执行函数，而只会创建一个立即丢弃的函数指针。

为了让您的代码工作，请考虑以下代码（注意代码中的注释，其中解释了所需的更改）：

#include <iostream>

class execute
{
public:
    void exec(char, double&, double, double);
}jalan;

class calculate {
public: // added static keyword so you do not need to create a class instance
    static void addition(double&, double, double);
    static void substraction(double&, double, double);
    static void multiply(double&, double, double);
    static void division(double&, double, double);
};

int main(void){
    static double a, b;
    static double result;
    std::cout << "Type a, b, c, or d" << std::endl;
    std::cout << "a. Addition\nb. Subtraction\nc. Multiply\nd. Division" << std::endl;
    std::cout << "Your Input: ";
    static char option;
    option = getchar();
    std::cout << "First value: ";
    std::cin >> a;
    std::cout << "Next value: ";
    std::cin >> b;
    jalan.exec(option, result, a, b);   // you need to pass the arguments which you want to use and modify
    std::cout << result << std::endl;
    return 0;
}

void execute::exec (char option, double& res, double a, double b){
    switch(option){  // changed the function pointers to actual calls to the functions
    case 'a' : calculate::addition(res, a, b); break;
    case 'b' : calculate::substraction(res, a, b); break;
    case 'c' : calculate::multiply(res, a, b); break;
    case 'd' : calculate::division(res, a, b); break;
    }   
}
void calculate::addition(double& result, double a, double b){
    result = a+b;   
}
void calculate::substraction(double& result, double a, double b){
    result = a-b;   
}
void calculate::multiply(double& result, double a, double b){
    result = a*b;   
}
void calculate::division(double& result, double a, double b){
    result = a/b;   
}

希望这有助于理解您的问题。

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