其他声明不适用

debugcn 发表于 Dev

尼科·洛科

为什么我的 PHP 代码中的最后一个 else 语句不起作用？当我输入不存在的帐户时，它没有显示“电子邮件或密码不正确”错误消息。

<?php

include("connection.php");

$email_id = $password = $emailErr = $passErr = $loginErr = "";

if(isset($_POST["butLogin"])){
    if(empty($_POST["email_id"])){
        $emailErr = "This field cannot be empty!";
    }else{
        $email_id = $_POST["email_id"];
    }

    if(empty($_POST["password"])){
        $passErr = "This field cannot be empty!";
    }else{
        $password = $_POST["password"];
    }

    if($email_id && $password){
        $check_record = mysqli_query($connection, "SELECT * FROM user WHERE password = '$password' AND email = '$email_id'");

        if (mysqli_num_rows($check_record) > 0 ){
            $row = mysqli_fetch_assoc($check_record);
            if(($email_id == $row['email']) && ($password == $row['password'])){
                if($row['user_type'] == 1){
                    header("Location: /php/admin/index");
                }else{
                    header("Location: /php/user/index");
                }
            }else{
                $loginErr = "Incorrect email or password.";
            }   
        }
    }
}
?>

维拉尔

如果 account 不存在，mysqli_num_rows 将返回 0。您应该在该块中移动 else 条件。

    if (mysqli_num_rows($check_record) > 0 ){
        $row = mysqli_fetch_assoc($check_record);
        if(($email_id == $row['email']) && ($password == $row['password'])){
            if($row['user_type'] == 1){
                header("Location: /php/admin/index");
            }else{
                header("Location: /php/user/index");
            }
        }   
    } else{
        $loginErr = "Incorrect email or password.";
    }

本文收集自互联网，转载请注明来源。

如有侵权，请联系[email protected] 删除。