我正在启动一个 Delphi 应用程序并为它创建一个互斥锁，如下所示：
var
AMutex: THandle;
function OpenMutex(const AMutexName: String): Boolean;
begin
{ Assume the Windows Mutext is already open }
Result := False;
{ Is the Mutex already open? }
if AMutex <> 0 then
exit;
{ Try to create Windows Mutex }
if CreateProgramMutex( AMutexName , AMutex) then
Result := True
else
AMutex := 0;
end;
function CreateProgramMutex( AMutexName: string; var AMutex: THandle ): boolean;
begin
{ Assume the new program mutex was created successfully. }
Result := true;
{ Attempt to create a new mutex. }
AMutex := CreateMutex(nil, False, PChar(AMutexName));
{ If we at least got a handle to the mutex... }
if (AMutex <> 0) then
begin
if GetLastError = ERROR_ALREADY_EXISTS then begin
{ Close the handle, since it already exists. }
CloseHandle(AMutex);
{ Set the return to show that it was already running. }
Result := false;
end;
end else
Result := false;
end;
我正在尝试从 C#（作为初学者）找出我的应用程序是否已经在控制台应用程序中运行：
using System;
using System.Threading;
namespace ConsoleApplication1
{
class OneAtATimePlease
{
private static Mutex _mutex;
private static bool IsSingleInstance()
{
_mutex = new Mutex(false, "my mutex name");
// keep the mutex reference alive until the normal
//termination of the program
GC.KeepAlive(_mutex);
try
{
return _mutex.WaitOne(0, false);
}
catch (AbandonedMutexException)
{
// if one thread acquires a Mutex object
//that another thread has abandoned
//by exiting without releasing it
_mutex.ReleaseMutex();
return _mutex.WaitOne(0, false);
}
}
static void Main()
{
if (!IsSingleInstance())
Console.WriteLine("already running");
Console.ReadLine();
}
}
}
即使 Delphi 应用程序正在运行，IsSingleInstance 也返回 true。使用相同的 Delphi 代码检查 Delphi 控制台应用程序中的互斥锁。我确信这是显而易见的，但我无法弄清楚我做错了什么。
PS：一切都在同一个 Windows 用户会话下完成
您说您的目标是检查外部应用程序是否正在运行（通过使用命名互斥锁）。好吧，对于这种情况，您不应尝试在应用程序中创建给定名称的互斥对象，而应尝试打开此类对象。原因很简单，如果那个外部应用程序使用这样的互斥锁来检查它是否自己运行，你实际上会为你的应用程序窃取这个互斥锁，而那个外来的应用程序将永远不会启动。
出于您的目的，请使用TryOpenExisting类函数。例如：
using System;
using System.Threading;
namespace ConsoleApp1
{
class Program
{
static void Main(string[] args)
{
Mutex mutex;
if (Mutex.TryOpenExisting("My unique mutex name", out mutex)) {
try {
// with the used TryOpenExisting overload you can work with
// the mutex object here; you can wait for it or release
Console.WriteLine("Application is running!");
}
finally {
mutex.Close();
}
}
else {
Console.WriteLine("Application is NOT running!");
}
Console.ReadLine();
}
}
}
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