Firebase Ionic - 返回错误

debugcn 发表于 Dev

ksa_coder

我有一个条件，我正在检查用户名是否被占用。如果没有，那么我检查电子邮件是否已注册（如果没有，则继续创建帐户）。我正在将 firebase 函数与业务逻辑分开......但我无法弄清楚如何将错误从 createUserWithEmailAndPassword() 返回到页面类以进一步处理。

if(usernameTaken) {


            }else{
                /*Username is available - Check email taken or not (if not, register)*/
                      var error = self.firebaseProvider.registerUser(self.email,self.password,self.username, self.name);

                if(error.code !== ""){
                    if(error.code == "auth/email-already-in-use"){
                        let alert = self.alertCtrl.create({
                          title: 'Email Exists',
                          subTitle: 'The email you entered is already registered.',
                          buttons: ['Retry']
                        });
                        alert.present();
                      }else if(error.code == 'auth/weak-password') {
                        let alert = self.alertCtrl.create({
                          title: 'Validation Error',
                          subTitle: 'The password entered is weak and should be 6 characters.',
                          buttons: ['Retry']
                        });
                        alert.present();
                      }
                }
            }

这是 firebase.ts 中的代码：

registerUser(email: string, password: string, username: string, name: string): (any) {
      var self = this;  

      this.fbAuth.auth.createUserWithEmailAndPassword(email, password).then(function() {
        var user = firebase.auth().currentUser;
        self.createUserRecord(username, email, name);    
      }).catch(function(error) {
        //Handle error
        return error;
      });

  }

返回的错误为空（未定义），因此没有按预期工作。请帮忙。

草图

您的代码需要进行一些重构，您的父调用期待一个承诺，因此var error将通过一个thenable对象，它不会有err.code.

同样error在您的registerUser类中返回一个作为成功响应的可能难以调试，因此最好在父调用上设置捕获句柄。

if (usernameTaken) {

} else 
  /*Username is available - Check email taken or not (if not, register)*/
  self.firebaseProvider.registerUser(self.email,self.password,self.username, self.name)
    .then(resp => {
      // Do Something
    })
    .catch(err => {
      if (error.code !== "") {
        if(error.code == "auth/email-already-in-use"){
          let alert = self.alertCtrl.create({
            title: 'Email Exists',
            subTitle: 'The email you entered is already registered.',
            buttons: ['Retry']
          });

          alert.present();
        } else if(error.code == 'auth/weak-password') {
          let alert = self.alertCtrl.create({
            title: 'Validation Error',
            subTitle: 'The password entered is weak and should be 6 characters.',
            buttons: ['Retry']
          });

          alert.present();
        }
      }
    });
}

您需要return在this.fbAuth.auth.createUserWithEmailAndPassword调用前添加一个。

registerUser(email: string, password: string, username: string, name: string): Promise<any> {
  var self = this;  

  return this.fbAuth.auth.createUserWithEmailAndPassword(email, password)
    .then(function() {
      var user = firebase.auth().currentUser;
      return self.createUserRecord(username, email, name);    
    });
}

现在，如果函数抛出一个错误就出现在父类的处理，你可以看到之间的差异createUserRecord和error。

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