我有一个简单的查询:
SELECT
c.nom AS race_name,
r.nom_coureur AS player_name,
r.prenom_coureur AS player_name_first
FROM pourvelobsx.calendrier AS c
INNER JOIN pourvelobsx.resultat_autre AS r
ON r.identifiant_epreuve = c.identifiant
WHERE nom_etape = "final"
ORDER BY c.id DESC
LIMIT 5
查询返回 5 行:
+------------------+-------------+-------------------+
| race_name | player_name | player_name_first |
+------------------+-------------+-------------------+
| Watashi wa Alex | BARBAS | Yoann |
| Watashi wa Alex | AHLSTRAND | Jonas |
| Watashi wa Alex | ACEVEDO | Janier Alexis |
| Tour de La Baule | CHAVANEL | Sylvain |
| Tour de La Baule | SANCHEZ | Samuel |
+------------------+-------------+-------------------+
我想知道,如何限制比赛的结果(“日历”表)而不是全局行结果?
像这样:
+------------------+-------------+-------------------+
| race_name | player_name | player_name_first |
+------------------+-------------+-------------------+
| Watashi wa Alex | BARBAS | Yoann |
| Watashi wa Alex | AHLSTRAND | Jonas |
| Watashi wa Alex | ACEVEDO | Janier Alexis |
| Tour de La Baule | CHAVANEL | Sylvain |
| Tour de La Baule | SANCHEZ | Samuel |
| Tour de La Groin | HELLO | Calvin |
| Tour de La Groin | ESTEBEZ | Millo |
| Tour de France | SANCHEZ | Samuel |
| Tour de France | SICKED | Alex |
| Tour d'Espagne | VILLIOD | Fred |
| Tour d'Espagne | CRACHER | Jordan |
| Tour d'Espagne | ELBANTI | Maxime |
| Tour d'Espagne | BOKEDRON | Yohan |
+------------------+-------------+-------------------+
所以我只有 5 场比赛,不限制排。我尝试过DISTINCT
但没有成功。
我相信你想要这样的东西
SELECT
c.nom AS race_name,
r.nom_coureur AS player_name,
r.prenom_coureur AS player_name_first
FROM pourvelobsx.calendrier AS c
INNER JOIN pourvelobsx.resultat_autre AS r ON r.identifiant_epreuve = c.identifiant
INNER JOIN
(
SELECT c.nom
FROM pourvelobsx.calendrier AS c
INNER JOIN pourvelobsx.resultat_autre AS r ON r.identifiant_epreuve = c.identifiant
WHERE nom_etape = "final"
GROUP BY c.nom
ORDER BY c.id DESC
LIMIT 5
) t ON t.nom = c.nom
WHERE nom_etape = "final"
本文收集自互联网,转载请注明来源。
如有侵权,请联系[email protected] 删除。
我来说两句