我提取了一些文本并希望通过 RegEx 清理它。
我已经学习了基本的 RegEx 但不知道如何构建这个：
str = '''
this is
a line that has been cut.
This is a line that should start on a new line
'''
应该转换成这样：
str = '''
this is a line that has been cut.
This is a line that should start on a new line
'''
这r'\w\n\w'似乎抓住了它，但不确定如何用空格替换新行而不触及单词的结尾和开头
您可以将这个lookbehind regex用于re.sub：
>>> str = '''
... this is
... a line that has been cut.
... This is a line that should start on a new line
... '''
>>> print re.sub(r'(?<!\.)\n', '', str)
this is a line that has been cut.
This is a line that should start on a new line
>>>
(?<!\.)\n 匹配所有前面没有点的换行符。
如果您不想根据点的存在进行匹配，请使用：
re.sub(r'(?<=\w\s)\n', '', str)
本文收集自互联网，转载请注明来源。
如有侵权，请联系[email protected] 删除。
我来说两句