我试图为不同的网址返回不同的模板(只有一个应用程序),所以基本上我想返回:
一个模板:http://127.0.0.1:8000/projects/
另一个模板:http://127.0.0.1:8000/formpage/
我有项目 urls.py:
from django.conf.urls import url,include
from django.contrib import admin
from appone import views
urlpatterns = [
url(r'^admin/', admin.site.urls),
#home page
url(r'^$', views.index, name='index'),
url(r'^projects/', include('appone.urls')),
url(r'^formpage/', include('appone.urls')),
]
和应用程序 urls.py:
from django.conf.urls import url,include
from django.http import HttpResponse
from . import views
urlpatterns = [
url(r'^$', views.projs, name='proj'),
url(r'^$', views.form_view, name='form_view')
]
我有很好的视图和模板,但我不明白如何根据 url 返回它们,因为目前我从应用程序 urls.py 返回了两个 url 的第一个视图。
为两个 url (projs
和form_view
)制作单独的视图函数。
然后在 projects/urls.py
urlpatterns = [
...
url(r'^projects/', views.projs, name='proj'),
url(r'^formpage/', views.form_view, name='form_view')
...
]`
或者,如果您想拥有单独的urls.py
文件
projects/urls.py
:
urlpatterns = [
url(r'^admin/', admin.site.urls),
#home page
url(r'^$', views.index, name='index'),
url(r'^', include('appone.urls')),
]`
appone/urls.py
urlpatterns = [
url(r'^projects/', views.projs, name='proj'),
url(r'^formpage/', views.form_view, name='form_view')
]`
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我来说两句