打印报表没有为我提供准确的数字

好的，问题来了，代码有效，但数字加起来不对，所以我在某处遗漏了一些东西。我的大脑因为连续三天工作而完全死了，所以我需要另一组眼睛。基本上这是一个评分计算器，它从 .txt 文件中获取输入并将输出发送到 .txt 文件。我正在放弃最低测验分数。我还需要一些有关 outfile.write(outstring) 格式的帮助，它现在到处都是，我需要它看起来与输出文件完全一样。我留下了一些诊断打印语句，但基本上这就是代码现在的样子：

infilename = input("Please enter file name: ")
outfilename = input("Please enter output file name: ")

infile = open(infilename,"r")
outfile = open(outfilename, "w")

quiz_sum = 0
low_quiz = 1000
prog_sum = 0

nameline = infile.readline()
outfile.write(nameline)
print(nameline)
while nameline != "":
    quiz_line = infile.readline()
    prog_line = infile.readline()
    exam_line = infile.readline()
    quiz_list=quiz_line.split()
    quiz_sum = 0
    prog_sum = 0
    low_quiz = 1000
    for quiz_score in quiz_list:
        quiz_float = float(quiz_score)
        quiz_sum += quiz_float
        if quiz_float < low_quiz:
            low_quiz = quiz_float
    if len(quiz_list) > 1:
        quiz_avg = ((quiz_sum-low_quiz)/(len(quiz_list)-1))*10
    else:
        quiz_avg = quiz_sum*10
    print("QUIZ AVERAGE", quiz_avg)
    prog_list = prog_line.split()
    for prog_score in prog_list:
        prog_float = float(prog_score)
        prog_sum += prog_float
    if len(prog_list) > 1:
        prog_avg = ((prog_sum) / len(prog_list))*10
    else:
        prog_avg = prog_sum*10
    print("PROGRAM AVERAGE", prog_avg)
    exam_list = exam_line.split()
    for exam_score in exam_list:
        exam_float = float(exam_score)
        #exam_sum += exam_float
    exam1 = float(exam_list[0])
    exam2 = float(exam_list[1])
    exam3 = float(exam_list[2])
    exam_avg = (exam1*.20)+(exam2*.20)+(exam3*.25)
    print("EXAMs" , exam1,exam2,exam3)
    average = ((quiz_avg*.15)+(prog_avg*.20)+(exam_avg))
    if 90 <= average <= 100:
        final_grade = "A"
    if 80 <= average < 90:
        final_grade = "B"
    if 70 <= average < 80:
        final_grade = "C"
    if 60 <= average < 70:
        final_grade = "D"
    if 0 <= average < 60:
        final_grade = "F"
    print("TOTAL AVERAGE",average)
    outstring =("%-20s %3.1f   %s" %(nameline,average,final_grade))
    print(outstring)
    outfile.write(outstring)
    nameline = infile.readline()
    outstring = ("%-20s***" % (nameline))

infile.close()
outfile.close()

这是输入的样子（第一行数字是测验，第二行是程序项目，第三行是考试 [分别是考试 1、2、3]）：

Babbage, Charles
10.0   9.5    8.0  9.0
 9.5  10.0    9.0
85.0  92.0   81.0
Turing, Alan
1.0   8.0    6.0
10.0  10.0    9.0   9.5
90.0  92.0   88.5
Hopper, Grace
10.0  5.0    8.0
10.0  10.0    9.0   9.5
90.0  92.0   88.0
Van Rossum, Guido
 7.5   8.5
 7.5   6.0    6.0   9.0
68.0  81.0   70.0
Backus, John
 9.5   3   10.0   8.0   9.5  10.0
 7.5   8.5    6.0   9.0  10.0
99.0  93.0  44.0
Crawley, Bryan
 6.0
 7.5
70.0  60.0   55.5

最后，这应该是输出的格式：

Babbage, Charles      89.4   B
Turing, Alan          91.3   A
Hopper, Grace         92.7   A
Van Rossum, Guido     75.5   C
Backus, John          94.4   A
Crawley, Bryan        63.9   D

tl;dr - 我需要获得正确的数字才能使该程序正常工作。我还需要有关程序如何在循环结束时写入文件的格式方面的帮助。谢谢你们。

编辑 -

更新帖子以显示当我运行程序时会发生什么：请输入文件名：scores.txt 请输入输出文件名：results.txt Babbage, Charles

QUIZ AVERAGE 95.0
PROGRAM AVERAGE 95.0
EXAMs 85.0 92.0 81.0
TOTAL AVERAGE 88.9
Babbage, Charles
    88.9   B
QUIZ AVERAGE 70.0
PROGRAM AVERAGE 96.25
EXAMs 90.0 92.0 88.5
TOTAL AVERAGE 88.275
Turing, Alan
        88.3   B
QUIZ AVERAGE 90.0
PROGRAM AVERAGE 96.25
EXAMs 90.0 92.0 88.0
TOTAL AVERAGE 91.15
Hopper, Grace
       91.2   A
QUIZ AVERAGE 85.0
PROGRAM AVERAGE 71.25
EXAMs 68.0 81.0 70.0
TOTAL AVERAGE 74.3
Van Rossum, Guido
   74.3   C
QUIZ AVERAGE 94.0
PROGRAM AVERAGE 82.0
EXAMs 99.0 93.0 44.0
TOTAL AVERAGE 79.9
Backus, John
        79.9   C
QUIZ AVERAGE 60.0
PROGRAM AVERAGE 75.0
EXAMs 70.0 60.0 55.5
TOTAL AVERAGE 63.875
Crawley, Bryan
      63.9   D

这就是“results.txt”文件中的内容：

Babbage, Charles
Babbage, Charles
    88.9   BTuring, Alan
        88.3   BHopper, Grace
       91.2   AVan Rossum, Guido
   74.3   CBackus, John
        79.9   CCrawley, Bryan
      63.9   D