我尝试使用以下方式传递日期但无法成功。dateAnswered 是将日期存储为 2017-09-13 00:00:00 的字段。
谁能告诉我哪里出错了：
方式一：设置参数
@NamedQuery(name = "findAnswar", query = "SELECT a FROM Answar a WHERE (a.dateAnswered = :currentDate )"
Try 1:
super.em.createNamedQuery( "findAnswar" , Answar .class ).setParameter( "currentDate", new Date() ); //Not receive any data
Try 2:
Date date = new Date();
date.setHours(0);
date.setMinutes(0);
date.setSeconds(0);
super.em.createNamedQuery( "findAnswar" , Answar .class ).setParameter( "currentDate", date) //Not receive any data
方式二：设置内置参数
@NamedQuery(name = "findAnswar", query = "SELECT a FROM Answar a WHERE (a.dateAnswered = current_date() )") //NOT WORKS
It works if i do add Temporal to getter:
@Column(name = "DATE_ANASWERED")
@Temporal(TemporalType.DATE)
public Date getDateAnswered () {
return dateAnswered ;
}
BUT IT GIVES another issue : Caused by: org.hibernate.HibernateException: Wrong column type in db.ANSWAR for column DATE_ANASWERED. Found: datetime, expected: date
@NamedQuery(name = "findAnswar", query = "SELECT a FROM Answar a WHERE (a.dateAnswered = current_date )") //NOT WORKS - JPA errors
即使在 Stackoverflow 的先前答案中，我也找不到任何相关的解决方案。任何人都可以帮助仅使用命名查询来修复相同的问题吗？
能够通过对命名查询进行以下更改来实现它，它就像魅力一样工作：
"SELECT a FROM Answar a WHERE cast(a.dateAnswered as date) = current_date()
由于基础类型是日期时间，所以我们需要将其转换为日期以使用 current_date()
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我来说两句