这是我的img
标签:
<img src="https://myserver.com/image?w=667&h=375 667w"
srcset="https://myserver.com/image?w=1366&h=1024 1366w 1x,
https://myserver.com/image?w=1366&h=1024&dpr=2 1366w 2x,
https://myserver.com/image?w=1366&h=1024&dpr=3 1366w 3x,
https://myserver.com/image?w=1024&h=768 1024w 1x,
https://myserver.com/image?w=1024&h=768&dpr=2 1024w 2x,
https://myserver.com/image?w=1024&h=768&dpr=3 1024w 3x,
https://myserver.com/image?w=800&h=480 800w 1x,
https://myserver.com/image?w=800&h=480&dpr=2 800w 2x,
https://myserver.com/image?w=800&h=480&dpr=3 800w 3x" sizes="100%">
我正在使用 imgix,它根据dpr
查询参数以正确的像素密度返回图像。以上似乎不起作用,图像未以正确的尺寸呈现。我没有使用正确的格式吗?
您不能在属性中混合使用x
和w
描述符srcset
。
我不知道 imgix,但我想?w=800&h=480&dpr=2
返回一个尺寸为 1600x960 像素的图像。是https://myserver.com/image?w=800&h=480&dpr=2和https://myserver.com/image?w=1600&h=960&dpr=1相同的图像?
如果图像在每个可见尺寸上始终相同(相同的内容和相同的纵横比),您应该定义您需要的可见/CSS 尺寸(取决于您的设计,例如 800、1200 和 1600 像素)并编写以下内容:
<img
src="https://myserver.com/image?w=800&h=400"
srcset="https://myserver.com/image?w=800&h=400 800w,
https://myserver.com/image?w=1200&h=600 1200w,
https://myserver.com/image?w=1600&h=800 1600w,
https://myserver.com/image?w=2000&h=1000 2000w,
https://myserver.com/image?w=2400&h=1200 2400w,
https://myserver.com/image?w=2800&h=1400 2800w,
https://myserver.com/image?w=3200&h=1600 3200w"
sizes="100vw">
该?w=2400&h=1200
图像将被浏览了几个配置下载:
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