如何获取javascript数组中重复项的索引？

debugcn 发表于 Dev

静音编码器14

我有一个这样的排序数组：

var a= [
    {id:"1", name:"A", address:"A"},
    {id:"2", name:"A", address:"B"},
    {id:"3", name:"A", address:"C"},
    {id:"4", name:"B", address:"A"},
    {id:"5", name:"B", address:"B"},
    {id:"6", name:"C", address:"A"},
    {id:"7", name:"C", address:"B"},
    {id:"8", name:"C", address:"C"},..

我想要做的是获取那些重复的“名称”的索引，例如

index 0-2 => "A";
index 3-4 => "B";
index 5-7 => "C";

或者甚至计算这些重复项都可以，例如3对于 A、2对于 B、3对于 C。

        var counter = 0;
        var prev = "";
        var next = "";
        var prevLink = a[0].name;

        for (var i = 0; i < a.length; i++) { 

         if(i >= ssRow.length){
             //do nothing
        }else{        
          next  = a[i+1].name;  
        } 

        if(prev== next){
          counter++;
        }else{        
          counter = 0;
          prevLink = a[i].name;      
        }
          //play with counter variable
        }

但它没有按预期工作。有没有更好的方法或有效的方法来做到这一点？

普拉奈·库马尔

 let dupes = {};
 const array= [
        {id:"1", name:"A", address:"A"},
        {id:"2", name:"A", address:"B"},
        {id:"3", name:"A", address:"C"},
        {id:"4", name:"B", address:"A"},
        {id:"5", name:"B", address:"B"},
        {id:"6", name:"C", address:"A"},
        {id:"7", name:"C", address:"B"},
        {id:"8", name:"C", address:"C"}];
 array.forEach((item,index) => {
   dupes[item.name] = dupes[item.name] || [];
   dupes[item.name].push(index);
 });       
 for(let name in dupes) console.log(name+'->indexes->'+dupes[name]+'->count->'+dupes[name].length)

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