当尝试从 Python 访问外部文本文件时,我在尝试简单地查看文件内容和尝试添加到文件时遇到了几个问题。所涉及的程序部分采用用户名,如果该用户名不存在,则在该用户名下创建一个文本文件。使用该Create()
功能时,我遇到以下情况TypeError
:
Exception in Tkinter callback
Traceback (most recent call last):
File "D:\Python 3.3.2\A Level Computer Science\stackoverflowsolution.py", line 48, in View
with open(userfile, 'r') as u:
FileNotFoundError: [Errno 2] No such file or directory: 'name.txt'
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "D:\Python 3.3.2\Python files\lib\tkinter\__init__.py", line 1475, in __call__
return self.func(*args)
File "D:\Python 3.3.2\A Level Computer Science\stackoverflowsolution.py", line 91, in Add
u.write(addText.get())
TypeError: get() missing 1 required positional argument: 'index1'
这是遇到错误的代码:
from tkinter import *
import os
def Login():
global nameEL
global rootA
rootA = Tk()
rootA.title('Login')
intruction = Label(rootA, text='Please Login\n')
intruction.grid(sticky=E)
nameL = Label(rootA, text='Username: ')
nameL.grid(row=1, sticky=W)
nameEL = Entry(rootA)
nameEL.grid(row=1, column=1)
loginB = Button(rootA, text='Login', command=LoggedIn)
loginB.grid(columnspan=2, sticky=W)
rootA.mainloop()
def LoggedIn():
global userfile
roots1 = Tk()
roots1.title('Logged in successfully')
roots1.geometry('300x300')
userfile = nameEL.get() + '.txt'
View1 = Button(roots1, text='View', command=View)
View1.grid(columnspan=10, sticky=W)
View1.pack(fill = 'x')
Create1 = Button(roots1, text='Create', command=Create)
Create1.grid(columnspan=10, sticky=W)
Create1.pack(fill = 'x')
def View():
global userfile
try:
with open(userfile, 'r') as u:
print(u.read())
except FileNotFoundError:
r = Tk()
r.title('View')
r.geometry('300x50')
rlbl = Label(r, text='\n[!] Theres nothing to see here [!]')
rlbl.pack()
r.mainloop()
LoggedIn()
except ValueError:
r = Tk()
r.title('View')
r.geometry('300x50')
rlbl.pack()
r.mainloop()
LoggedIn()
def Create():
global addText
global rootC
rootC = Tk()
rootC.title('Lets add some information')
instruction = Label(rootC, text='Please enter the information you would like to add\n')
instruction.grid(row=0, column=0, sticky=W)
newText = Label(rootC, text='info: ')
newText.grid(row=1, column=0)
addText = Text(rootC)
addText.grid(row=2, column=0)
addButton = Button(rootC, text='Add', command=Add)
addButton.grid(columnspan=2, sticky=W)
addButton.grid(row=3, column=0)
def Add():
global userfile
with open(userfile, 'a') as u:
u.write(addText.get())
u.write('\n')
rootC.destroy()
LoggedIn()
Login()
我会这样做:
def LoggedIn():
global userfile
roots1 = Tk()
roots1.title('Logged in successfully')
roots1.geometry('300x300')
userfile = nameEL.get() + '.txt'
#and the tkinter widgets
这段代码userfile = open(nameEL.get() + '.txt', 'a')
有点奇怪,您正在使用该open
命令创建一个对象,稍后将其用作字符串。你只需userfile
要是一个字符串,而不是一个命令。然后,您可以使用它打开文件(见下文)
def View():
global userfile
try:
with open (userfile, 'r') as u:
print (u.read())
except FileNotFoundError: #file doesn't exist
r = Tk()
r.title('View')
r.geometry('300x50')
rlbl = Label(r, text='\n[!] This file doesn't exist [!]')
rlbl.pack()
r.mainloop()
LoggedIn()
except ValueError: #some error when reading
r = Tk()
r.title('View')
r.geometry('300x50')
rlbl = Label(r, text='\n[!] Problem when reading the file [!]')
rlbl.pack()
r.mainloop()
LoggedIn()
在这里,print(userfile.read())
不起作用,因为您userfile
使用append
模式创建(也许还有其他问题)
最后
def Add():
global userfile
with open(userfile, 'a') as u:
u.write(addText.get()) #don't forger the .get ()
u.write('\n')
rootC.destroy()
LoggedIn()
在这里,您试图Entry
在文件中写入一个对象,Python 不喜欢那样。您只需要添加.get()
以便它写入Entry
对象中的内容addText
。这里还有一个错误:使用with ()
命令时,您不需要关闭文件,它会自动完成。可能仍然存在问题,但文件应该可以正常工作。
编辑:当使用Text
小部件时,get() 命令需要比仅使用Entry
小部件时更多的参数您可以使用:
u.write (addText.get('1.0', END))
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