DECLARE
TEAM_ID NUMBER := &INPUT;
CURSOR C_WORKER IS
SELECT FIRST_NAME, LAST_NAME
FROM EMPLOYEES
WHERE DEPARTMENT_ID = TEAM_ID;
V_LAST_NAME EMPLOYEES.LAST_NAME%TYPE;
V_FIRST_NAME EMPLOYEES.FIRST_NAME%TYPE;
BEGIN
OPEN C_WORKER;
LOOP
FETCH C_WORKER INTO V_LAST_NAME, V_FIRST_NAME;
EXIT WHEN C_WORKER%NOTFOUND;
DBMS_OUTPUT.PUT_LINE(V_LAST_NAME || ' ' || V_FIRST_NAME);
END LOOP;
CLOSE C_WORKER;
END;
我如何更改此代码以检查 TEAM_ID(&input) 是否为数字?如果是 - 打开光标,如果不是,打印“请写一个数字”。
最小值是 1,最大值是 TEAM_ID 的最大数量?或者它只是一个数字?
要处理替换变量,您需要将它们用引号括起来并将它们视为字符串。
例如,这可能是一种执行您需要的操作的方法:
declare
-- define a varchar2 variable to host your variable; notice the quotes
vStringInput varchar2(10) := '&input';
vNumInput number;
vVal number;
-- define a parametric cursor, to avoid references to variables
cursor cur(num number) is select num from dual;
begin
-- try to convert the string to a number
begin
vNumInput := to_number(vStringInput);
exception
when others then
vNumInput := null;
end;
--
-- check the values, to understand if it is a number ( vNumInput NULL or NOT NULL)
-- and, in case it's a number, if it suits your criteria
case
when vNumInput is null then
dbms_output.put_line('not a number');
when vNumInput < 1 then
dbms_output.put_line('less than 1');
-- whatever check you need on the numeric value
else
-- if the value is ok, open the cursor
open cur(vNumInput);
loop
fetch cur into vVal;
exit when cur%NOTFOUND;
dbms_output.put_line('value from cursor: ' || vVal);
end loop;
end case;
end;
/
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