单击提交时，Bootstrap 和 PHP 联系表单显示空白页

1. submit 变量永远不会在您的表单中设置。请注意，该按钮现在是具有提交名称属性的提交类型的输入。

2. 您的其他表单变量也未设置。

3. 你从来没有回应任何事情。所以我在你的最后一个条件中放了一个回声。

4. 如果您希望表单在提交表单后显示，您需要将您的 index.html 重命名为 index.php 并在顶部包含 contact.php。见下文。

5. 如果您只是简单地检查 $_POST 变量是否为真，PHP 将抛出 E_NOTICE 错误。所以最好将变量包装到isset()（就像这个变量集一样）函数中。见下文。

我重构以防止 E_NOTICE 错误并评论更改。

联系方式

<?php
if (isset($_POST["submit"])) {

    $error = [];

    $name = $_POST['name'];
    $email = $_POST['email'];
    $message = $_POST['message'];
    /*$human = intval($_POST['human']); */
    $from = 'Geofrey Zellah';
    $to = '[email protected]';
    $subject = 'Message from Geofrey Zellah ';

    $body = "From: $name\n E-Mail: $email\n Message:\n $message";

    // Check if name has been entered
    if (!isset($_POST['name']) || strlen($_POST['name']) === 0) {
        $error['name'] = 'Please enter your name';
    }

    // Check if email has been entered and is valid
    if (!isset($_POST['email']) || !filter_var($_POST['email'], FILTER_VALIDATE_EMAIL)) {
        $error['email'] = 'Please enter a valid email address';
    }

    //Check if message has been entered
    if (!isset($_POST['message']) || strlen($_POST['name']) === 0) {
        $error['message'] = 'Please enter your message';
    }

    /*
    //Check if simple anti-bot test is correct
    if ($human !== 5) {
        $errHuman = 'Your anti-spam is incorrect';
    } */

// If there are no errors, send the email
    if (empty($error)) {
        if (mail ($to, $subject, $body, $from)) {
            $result='<div class="alert alert-success">Thank You! I will be in touch</div>';
        } else {
            $result='<div class="alert alert-danger">Sorry there was an error sending your message. Please try again later</div>';
        }
    }

}
?>

index.php <-- 注意文件扩展名的变化

<?php include 'contact.php';?>
<div class="container">
    <div class="row">
        <div class="col-md-6 col-md-offset-3" id="offer">

            <h2 id="form"> LET'S WORK ? </h2>

        </div>

        <div class="col-md-6 col-md-offset-3">

            <form role="form" method="post">

                <div class="form-group">
                    <input name="name" type="text" class="form-control" placeholder="Enter Your Name">
                    <?php if(isset($error['name'])) echo '<p class="text-danger">'.$error['name'].'</p>'; ?>
                </div>

                <div class="form-group">

                    <input name="email" type="email" class="form-control" id="exampleInputEmail1" placeholder="Enter Your Email">
                    <?php if(isset($error['email'])) echo '<p class="text-danger">'.$error['email'].'</p>'; ?>
                </div>

                <div class="form-group">
                    <textarea name="message" class="form-control" id="textarea1" rows="3" placeholder="Enter Your Message here"> </textarea>
                    <?php if(isset($error['message'])) echo '<p class="text-danger">'.$error['message'].'</p>'; ?>

                </div>

                <div class="form-group">
                    <input name="submit" type="submit" class="default-submit btn btn-large propClone bg-fast-pink btn-circle font-weight-300 text-white tz-text">SEND MESSAGE</input>
                </div>

                <div class="form-group">
                    <div class="col-sm-10 col-sm-offset-2">
                        <?php if(isset($result)) echo $result; ?>
                    </div>
                </div>
            </form>
        </div>

    </div>
</div>

更新

如果您不想在提交表单时重新加载页面，您将需要一些 jQuery ajax 操作并更改您的 HTML 和 PHP 文件。

首先删除我们之前添加的 index.php 的第一行：

 <?php include 'contact.php';?><!-- Remove this one -->

您不希望包含该文件，而是希望向其发送数据。

接下来编辑 HTML 文件并在 HTML 下包含 jQuery 库（在 HTML 下执行 JS 内容的常见做法）。然后相应地更改您的 PHP 文件。

所以你的新 HTML：

<div class="container">
    <div class="row">
        <div class="col-md-6 col-md-offset-3" id="offer">

            <h2 id="form"> LET'S WORK ? </h2>

        </div>

        <div class="col-md-6 col-md-offset-3">

            <form role="form" name="contact" method="post">

                <div class="form-group">
                    <input name="name" type="text" class="form-control" placeholder="Enter Your Name" value="test">
                </div>

                <div class="form-group">

                    <input name="email" type="email" class="form-control" id="exampleInputEmail1" placeholder="Enter Your Email" value="[email protected]">
                </div>

                <div class="form-group">
                    <textarea name="message" class="form-control" id="textarea1" rows="3" placeholder="Enter Your Message here">test </textarea>
                </div>

                <div class="form-group">
                    <input name="submit" type="submit" class="default-submit btn btn-large propClone bg-fast-pink btn-circle font-weight-300 text-white tz-text" value="SEND MESSAGE">
                </div>

                <div class="form-group" id="result">
                </div>
            </form>
        </div>

    </div>
</div>

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script type="text/javascript">
    $(document).ready(function(){ // launch when DOM is fully loaded

        $('form[name="contact"]').submit(function(event){ // fire when you hit submit

            event.preventDefault(); // prevent default form submission since you want to send data via ajax

            $('#result').html('');
            $('.alert').remove();

            var values = $(this).serialize();

            // Post form data to your contact.php script and work with response
            $.ajax({
                url: "contact.php",
                type: "POST",
                data: values ,
                success: function (response) {

                    if(response.success) {
                        $('#result').html('<div class="alert alert-success">'+response.success+'</div>');
                    }
                    if(response.error_form) {
                        $.each( response.error_form, function( key, value ) {
                            $('input[name="'+key+'"]').parent().append('<p class="help-block text-danger">'+value+'</p>');
                        });
                    }
                    if(response.error_mail) {
                        $('#result').html('<div class="alert alert-danger">'+response.error_mail+'</div>');
                    }

                },
                error: function(jqXHR, textStatus, errorThrown) {
                    console.log(textStatus, errorThrown);
                }


            });

        });
    });
</script>

最后改变了 PHP：

<?php

ini_set('display_errors',0);
$result = [];

// Check if name has been entered
if (!isset($_POST['name']) || strlen($_POST['name']) === 0) {
    $result['error_form']['name'] = 'Please enter your name';
}

// Check if email has been entered and is valid
if (!isset($_POST['email']) || !filter_var($_POST['email'], FILTER_VALIDATE_EMAIL)) {
    $result['error_form']['email'] = 'Please enter a valid email address';
}

//Check if message has been entered
if (!isset($_POST['message']) || strlen($_POST['message']) === 0) {
    $result['error_form']['message'] = 'Please enter your message';
}

/*
//Check if simple anti-bot test is correct
if ($human !== 5) {
    $errHuman = 'Your anti-spam is incorrect';
} */

// If there are no errors, send the email
if (empty($result['error_form'])) {


    $name = $_POST['name'];
    $email = $_POST['email'];
    $message = $_POST['message'];
    /*$human = intval($_POST['human']); */
    $from = 'Geofrey Zellah';
    $to = '[email protected]';
    $subject = 'Message from Geofrey Zellah ';

    $body = "From: $name\n E-Mail: $email\n Message:\n $message";

    if (mail ($to, $subject, $body, $from)) {
        $result['success']='Thank You! I will be in touch';
    } else {
        $result['error_mail']='Sorry there was an error sending your message. Please try again later';
    }
}

header('Content-type: application/json'); // tell browser what to expect
echo json_encode($result); // encode array to json object so javascript can work with it

我做了一个如此详尽的例子，因为许多人在成功发送常规表单后决定使用 ajax，但请注意页面重新加载;)