如何在Pygame中同时检测鼠标左键和右键单击

您可以为文档中概述的场景编写代码（按下按钮 1 和按下按钮 3 时会触发鼠标中键 2）。

mouse_pressed = pygame.mouse.get_pressed()
if (mouse_pressed[0] and mouse_pressed[2]) or mouse_pressed[1]:
    print("left and right clicked")

请记住，使用 pygame.mouse.get_pressed() 通常会非常快地触发，这意味着 if 语句中的任何代码都会在您释放鼠标键之前发生几次。这是因为 get_pressed() 始终返回所有鼠标按钮的状态。如果您想跟踪被按住的按钮，此方法非常有用。

我会将解决方案编码到 pygame.event.get() 中。这只会在事件发生时触发，因此只会触发一次：

left_mouse_down = False
right_mouse_down = False
while True:
    for event in pygame.event.get():
        if event.type == pygame.MOUSEBUTTONDOWN:
            if event.button == 1:
                left_mouse_down = True
                if right_mouse_down:
                    print("perform action")
                else:
                    print("action for single left click")
            if event.button == 3:
                right_mouse_down = True
                if left_mouse_down:
                    print("perform action")
                else:
                    print("action for single right click")
        elif event.type == pygame.MOUSEBUTTONUP:
            if event.button == 1:
                left_mouse_down = False
            if event.button == 3:
                 right_mouse_down = False

更新- 模拟第三次鼠标点击两键鼠标

上面的代码有效，但前提是您接受单个右或左动作也会触发的事实，但在组合（左/右）动作之前。如果这适用于您的游戏设计，那就试试吧。如果这是不可接受的，那么以下将起作用（尽管更深入一些）：

left_mouse_down = False
right_mouse_down = False
left_click_frame = 0  # keeps track of how long the left button has been down
right_click_frame = 0  # keeps track of how long the right button has been down
left_right_action_once = True  # perform the combo action only once
left_action_once = True  # perform the left action only once
right_action_once = True  # perform the right action only once
max_frame = 2  # The frames to wait to see if the other mouse button is pressed (can be tinkered with)
performing_left_right_action = False  # prevents the off chance one of the single button actions running on top of the combo action
while True:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            sys.exit()

    mouse_pressed = pygame.mouse.get_pressed()
    if mouse_pressed[0]:  # left click
        left_click_frame += 1
        left_mouse_down = True
    else:
        left_action_once = True
        left_mouse_down = False
        left_click_frame = 0

    if mouse_pressed[2]:  # right click
        right_click_frame += 1
        right_mouse_down = True
    else:
        right_action_once = True
        right_mouse_down = False
        right_click_frame = 0

    if not mouse_pressed[0] and not mouse_pressed[2]:
        left_right_action_once = True
        performing_left_right_action = False

    if left_mouse_down and right_mouse_down and abs(left_click_frame - right_click_frame) <= max_frame:
        if left_right_action_once:
            print("performing right/left action")
            left_right_action_once = False
            performing_left_right_action = True
    elif left_mouse_down and left_click_frame > max_frame and not performing_left_right_action and not right_mouse_down:
        if left_action_once:
            print("perform single left click action")
            left_action_once = False
    elif right_mouse_down and right_click_frame > max_frame and not performing_left_right_action and not left_mouse_down:
        if right_action_once:
            print("perform single right click action")
            right_action_once = False

关于这个问题的难点在于一次只能发生一个事件，因此您必须有一种方法知道左键单击是否被按下，除非您确定右键单击也不会被按下，否则不要对其进行评估。您可以通过跟踪帧来实现这一点，如果左右发生在一定数量的帧 (max_frames) 内，那么您可以右击/左击。否则你要么左要么右。

action_once 变量很重要，因为 pygame.mouse.get_pressed() 每次通过游戏循环都会检查每个鼠标按钮的状态，因此您需要一个标志来防止您的操作在按住按钮时多次运行（即使在点击的短暂持续时间）。游戏循环比鼠标点击快。

因此涵盖了所有三个场景：左单、右单、左右组合。换句话说，它模拟了在双键鼠标上的“第三次”鼠标点击......虽然解决方案相当笨重