反序列化 JSON

debugcn 发表于 Dev

安迪

由于返回的字段不同，我正在努力反序列化下面的 JSON 片段，例如在配置中，它可以与 config.on 一起使用，因为这是在每个配置块中，但由于其他配置块都不同，我该怎么做绕过这个？JSON 返回所有不同的传感器与不同的字段连接。

dynamic obj = JsonConvert.DeserializeObject(response);
//
foreach (var item in obj)
{
    string temperature = item.ToString();         //this shows the full object in text
    //    Debug.WriteLine(temperature);           //this shows the full object in text

    dynamic group = item;

    string idstring = group.Name.ToString();

    foreach (var prop in group)
    {
        string name = prop.name; 
        string temp = prop.config.on;
        //string temp = prop.state.lastupdated;
        //string temp = prop.swversion;

        //Debug.WriteLine(temp);

        string namestring = name.ToString();
        string tempstring = temp.ToString();

        arr[0] = idstring.ToLower();
        arr[1] = namestring.ToLower();
        arr[2] = tempstring.ToLower();

带有部分 JSON 响应

{
    "1": {
        "state": {
            "daylight": true,
            "lastupdated": "2017-03-10T07:01:00"
        },
        "config": {
            "on": true,
            "configured": true,
            "sunriseoffset": 30,
            "sunsetoffset": -30
        },
        "name": "Daylight",
        "type": "Daylight",
        "modelid": "PHDL00",
        "manufacturername": "Philips",
        "swversion": "1.0"
    },
    "2": {
        "state": {
            "temperature": 1830,
            "lastupdated": "2017-03-10T08:11:51"
        },
        "config": {
            "on": true,
            "battery": 100,
            "reachable": true,
            "alert": "none",
            "ledindication": false,
            "usertest": false,
            "pending": [

},
"name": "Hall",
"type": "ZLLPresence",
"modelid": "SML001",
"manufacturername": "Philips",
"swversion": "6.1.0.18912",
"uniqueid": "00:17:88:01:02:01:8b:be-02-0406"
  },
 "4": {
    "state": {
  "lightlevel": 12270,
  "dark": true,
  "daylight": false,
  "lastupdated": "2017-03-10T08:14:28"
},
"config": {
  "on": true,
  "battery": 100,
  "reachable": true,
  "alert": "none",
  "tholddark": 16011,
  "tholdoffset": 7000,
  "ledindication": false,
  "usertest": false,
  "pending": [

  ]
},
"name": "Hue ambient light sensor 1",
"type": "ZLLLightLevel",
"modelid": "SML001",
"manufacturername": "Philips",
"swversion": "6.1.0.18912",
"uniqueid": "00:17:88:01:02:01:8b:be-02-0400"
  },
  "5": {
"state": {
  "temperature": 1919,
  "lastupdated": "2017-03-10T08:12:50"

雷纳茨·斯托兹科夫

将缺失的属性转换为String多次不需要额外的创意。因此，不要这样做：

string namestring = name.ToString();
string tempstring = temp.ToString();

您只需预先检查null条件（如果需要）并采取相应措施。如果缺少某个属性，Json.NET 不会抛出异常，因此您可以尝试获取您需要的所有字段，然后相应地执行业务逻辑：

string name = prop.name;
string temp = prop.config.on;
string battery = prop.config.battery;
if (battery == null) 
    // maybe throw exception, maybe assign default value; whatever fits you

本文收集自互联网，转载请注明来源。

如有侵权，请联系[email protected] 删除。