如何将函数的返回值赋给局部变量？

debugcn 发表于 Dev

阿南丹

我需要使用 Type Script 将函数的返回值分配给局部变量。下面我已经清楚地解释了它：

getdetail1(store){              
    let Cust_id=this.sharedata.latus_lead.m_type
    let url="http:domain.com"
    console.log(url);
    let res;
    this.loginservice.leaddata = null;
    this.loginservice.getdetails(url).then(data=>{
        let lead=data;
        this.details=lead[0];
        res=lead[0];                          
    });
    return res;
}

并这样称呼它：

let res = this.getdetail1(store);

看这是我的登录服务代码

getdetails(query){
       if (this.leaddata) {
        // already loaded data  
        console.log("already data loaded lead") ;
        return Promise.resolve(this.leaddata);
      }
    // don't have the data yet
    return new Promise(resolve => {
      // We're using Angular HTTP provider to request the data,
      // then on the response, it'll map the JSON data to a parsed JS object.
      // Next, we process the data and resolve the promise with the new data.
        this.http.get(query)
        .map(res => res.json())
        .subscribe(data => {
          // we've got back the raw data, now generate the core schedule data
          // and save the data for later reference
          this.leaddata = data;
          resolve(this.leaddata);
        });
    });

  }

我在这里处理承诺

萨加尔·库尔卡尼

您需要从代码中返回一个承诺而不是一个变量。像这样：

getdetail1(store){              
    let Cust_id=this.sharedata.latus_lead.m_type
    let url="http:domain.com"
    console.log(url);
    let res;
    this.loginservice.leaddata = null;

    return this.loginservice.getdetails(url);
}

并这样称呼它：

this.getdetail1(store)
    .then((data) => {
        let res = data;
        console.log("Your data: ",res);
    })
    .catch((err) => {
        console.log("Error occurred :", err);
    });

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