在数组中搜索返回错误结果

debugcn 发表于 Dev

VLS

我收到了这样的数组

Array
(
    [hash] => 9761d3233f9cb256c0992be

    [total] => 2736712601    
    [received] => 2017-01-13T21:43:32.047Z
    [income] => Array
    (
        [0] => Array
            (
                [value] => 647262
                [addresses] => Array
                    (
                        [0] => Address_1
                    )
            )

        [1] => Array
            (
                [value] => 17200000
                [addresses] => Array
                    (
                        [0] => Address_2
                    )
            )

        [2] => Array
            (
                [value] => 3729034
                [addresses] => Array
                    (
                        [0] => Address_3
                    )
            )

        [3] => Array
            (
                [value] => 2414997500
                [addresses] => Array
                    (
                        [0] => Address_4
                    )
            )

        [4] => Array
            (
                [value] => 10856454
                [addresses] => Array
                    (
                        [0] => Address_5
                    )
            )
     )
)

因此，我在数据库中存储了哈希（9761d3233f9cb256c0992be）。我哈希和地址。然后根据它们，我匹配来自的正确数组[income]。当我在中找到正确的地址时，income我[value]会将其显示在页面上。这是我的方法

$url=get_curl_content("https://example.com/".$order->hash);

$totala =json_decode($url,true);

....
$match = true;
foreach ($totala['income'] as $data) {
    if ($data['addresses'] == $order->address) {
            $match = $data;
            break;
    }
}                     
$price = $data['value'];

问题是，我期望如此，Address_2因为在数据库中我已经保存Address_2了，Address_3而我已经保存了。

当我var_dump($data['addresses'])得到的时候Address_3。可能是什么问题？

尝试这样。它将使用in_array函数在数组中搜索和匹配

$match = true;

foreach ($totala['income'] as $data) {

    if (in_array($order->address, $data['addresses'])) {
            $match = $data;
            break;
    }                         

}                     
$price = $match['value'];

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