我正在玩gmock,我有一个人为设计的例子来学习它的细微差别。我在调用隐式副本构造函数时遇到了问题:
// mock_word.h
class MockWord : Word {
public:
MockWord(const std::string word) : Word(word) {};
MOCK_METHOD0(pigLatinify, std::string(void));
};
// strings.h
template <typename Word>
class Strings {
...
private:
std::vector<Word>* words = new std::vector<Word>();
public:
// This should call the implicit copy constructor
void addWord(const Word word) {
this->words->push_back(word);
};
...
};
// strings_test.cpp
class StringsTest : public ::testing::Test {
protected:
Strings<MockWord>* strings;
public:
virtual void SetUp() {
strings = new Strings<MockWord>();
};
virtual void TearDown() {
delete strings;
};
};
TEST_F(StringsTest, StringIsAllPigLatinifiedNicely) {
MockWord mockWordA("beast");
MockWord mockWordB("dough");
// Set some expectations for the Mock
EXPECT_CALL(mockWordA, pigLatinify()).Times(AtLeast(1));
EXPECT_CALL(mockWordB, pigLatinify()).Times(AtLeast(1));
strings->addWord(mockWordA);
strings->addWord(mockWordB);
...
};
现在,如果我将自动变量转换为指针mockWordA
并mockWordB
从指针转换,我可能会感到满意并且可以工作,但这不是我想要提供的接口。
我得到的确切错误是:
error: call to implicitly-deleted copy constructor of 'MockWord'
strings->addWord(mockWordA);
^~~~~~~~~
mock_word.h:11:9: note: copy constructor of 'MockWord' is implicitly deleted because field 'gmock0_pigLatinify_11' has a deleted copy constructor
MOCK_METHOD0(pigLatinify, std::string(void));
我通过更改函数接口解决了这个问题,Strings::addWord(Word* word)
因为我不想在这样的基本示例中使用指针,但对我来说,函数接口似乎是限制性的。
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