我希望我的HQL返回Object而不是array,因为我使用了一些联接表,并且当我编写一个包含联接表的列名的查询时,HQL会给出数组列表而不是object。我发现我们应该使用new
它作为对象。
SELECT new Accommodation(a.name, a.rank, ap.pic) FROM Accommodation AS a INNER JOIN a.accommodationPics AS ap WHERE ap.isPromoPic = 1 AND a.cbState.stateName = :stateName
到目前为止,我已经尝试过此操作,但出现错误:'Accommodation' cannot be resolved to a type.
。有什么不对?
更新
新查询: SELECT new ba.reservation.pojo.Accommodation(a.name, a.rank, ap) FROM Accommodation AS a INNER JOIN a.accommodationPics AS ap WHERE ap.isPromoPic = 1 AND a.cbState.stateName = :stateName
@Column(name = "name", nullable = false, length = 200)
private String name;
@Column(name = "rank")
private int rank;
@OneToMany(mappedBy = "accommodationBean", fetch = FetchType.EAGER, cascade = CascadeType.REMOVE)
@JsonManagedReference
private List<AccommodationPic> accommodationPics;
public Accommodation(String _name, int _rank, ArrayList<AccommodationPic> _pic) {
this.rank = _rank;
this.name = _name;
this.accommodationPics = _pic;
}
关于此查询:
错误有两个顺序:
第一个(如simas_ch所说):
使用新的Object(对于您的情况Accomodation
)时,必须使用所有名称空间路径完全限定您的Object
第二:
您必须在pojo定义中定义适当的构造函数。
如果您这样写:
new Accommodation(a.name, a.rank, ap.pic)
您必须在Accomodation
类中具有如下构造函数:
public Accommodation(String name, int rank, a.name, ArrayList<AccommodationPic> pic) {
this.name = name;
this.rank = rank;
this.pic = pic;
}
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