{
"status":"ok",
"cookie":"dr.steve|akscjn",
"cookie_name":"wordpress_logged_in",
"user": {
"id":330,
"username":"dr.steve",
"nicename":"steve",
"email":"[email protected]",
"url":"http:\/\/www.company.com",
"registered":"2016-12-15 22:21:05",
"displayname":"Dr.Steve",
"firstname":"Dr",
"lastname":"Steve",
"nickname":"steve",
"description":"Lorem ipsum",
"capabilities":"",
"avatar":null
}
}
我有这个json响应，我想要这个json的唯一id字段，我认为有两个嵌套数组，但是我遇到了错误
E /错误：Json解析错误：org.json.JSONObject类型的用户的值{“ id”：330，.........}无法转换为JSONArray
这是我的代码
if (jsonStr != null) {
try {
JSONArray ja = new JSONObject(jsonStr).getJSONArray("user");
JSONObject c = ja.getJSONObject(1);
String id = c.getString("id");
temp2 = id;
Log.v("id---->",temp2);
}
} catch (final JSONException e) {
Log.e("Error", "Json parsing error: " + e.getMessage());
runOnUiThread(new Runnable() {
@Override
public void run() {
Toast.makeText(getApplicationContext(),
"Json parsing error: " + e.getMessage(),
Toast.LENGTH_LONG)
.show();
}
});
}
} else {
Log.e("Error", "Couldn't get json from server.");
runOnUiThread(new Runnable() {
@Override
public void run() {
Toast.makeText(getApplicationContext(),
"Couldn't get json from server. Check LogCat for possible errors!",
Toast.LENGTH_LONG)
.show();
}
});
}
谁能告诉我我在哪里弄错了，我怎么从这个json中获取id字段？
该user属性是一个具体的对象，而不是数组，因此请尝试将其作为对象读取：
JSONObject user = new JSONObject(jsonStr).getJSONObject("user");
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我来说两句